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A car is moving with an acceleration of - 20m/s². If the car takes two seconds to stop after the application of breaks, calculate the velocity with which it was travelling.?
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A car is moving with an acceleration of - 20m/s². If the car takes two...
**Calculating the initial velocity of the car**
To calculate the initial velocity of the car, we need to use the equation of motion:
v = u + at
Here,
v = final velocity (0 m/s, as the car comes to a stop)
u = initial velocity (unknown)
a = acceleration (-20 m/s²)
t = time taken to stop (2 seconds)
**Substituting the values into the equation**
0 = u + (-20) * 2
Simplifying the equation, we have:
0 = u - 40
**Solving for the initial velocity**
To solve for the initial velocity, we need to isolate u on one side of the equation. By adding 40 to both sides of the equation, we get:
40 = u
Therefore, the initial velocity (u) of the car was 40 m/s.
**Explanation**
The given information states that the car has an acceleration of -20 m/s². The negative sign indicates that the car is decelerating or slowing down. This negative acceleration is caused by the application of brakes.
The problem also states that the car takes 2 seconds to stop after the application of brakes. This can be interpreted as the time it takes for the car to go from its initial velocity to a final velocity of 0 m/s (as it comes to a stop).
Using the equation of motion v = u + at, we substitute the given values. The final velocity is 0 m/s, the acceleration is -20 m/s², and the time is 2 seconds. Solving for the initial velocity (u), we find that it was 40 m/s.
Therefore, the car was traveling at an initial velocity of 40 m/s before the application of brakes.
To calculate the initial velocity of the car, we need to use the equation of motion:
v = u + at
Here,
v = final velocity (0 m/s, as the car comes to a stop)
u = initial velocity (unknown)
a = acceleration (-20 m/s²)
t = time taken to stop (2 seconds)
**Substituting the values into the equation**
0 = u + (-20) * 2
Simplifying the equation, we have:
0 = u - 40
**Solving for the initial velocity**
To solve for the initial velocity, we need to isolate u on one side of the equation. By adding 40 to both sides of the equation, we get:
40 = u
Therefore, the initial velocity (u) of the car was 40 m/s.
**Explanation**
The given information states that the car has an acceleration of -20 m/s². The negative sign indicates that the car is decelerating or slowing down. This negative acceleration is caused by the application of brakes.
The problem also states that the car takes 2 seconds to stop after the application of brakes. This can be interpreted as the time it takes for the car to go from its initial velocity to a final velocity of 0 m/s (as it comes to a stop).
Using the equation of motion v = u + at, we substitute the given values. The final velocity is 0 m/s, the acceleration is -20 m/s², and the time is 2 seconds. Solving for the initial velocity (u), we find that it was 40 m/s.
Therefore, the car was traveling at an initial velocity of 40 m/s before the application of brakes.
Community Answer
A car is moving with an acceleration of - 20m/s². If the car takes two...
40m/s
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A car is moving with an acceleration of - 20m/s². If the car takes two seconds to stop after the application of breaks, calculate the velocity with which it was travelling.?
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A car is moving with an acceleration of - 20m/s². If the car takes two seconds to stop after the application of breaks, calculate the velocity with which it was travelling.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car is moving with an acceleration of - 20m/s². If the car takes two seconds to stop after the application of breaks, calculate the velocity with which it was travelling.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving with an acceleration of - 20m/s². If the car takes two seconds to stop after the application of breaks, calculate the velocity with which it was travelling.?.
A car is moving with an acceleration of - 20m/s². If the car takes two seconds to stop after the application of breaks, calculate the velocity with which it was travelling.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car is moving with an acceleration of - 20m/s². If the car takes two seconds to stop after the application of breaks, calculate the velocity with which it was travelling.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving with an acceleration of - 20m/s². If the car takes two seconds to stop after the application of breaks, calculate the velocity with which it was travelling.?.
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