JEE Exam > JEE Questions > If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then...
Start Learning for Free
If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is?
Most Upvoted Answer
If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation li...
Interval in which roots lie:
• Given equation: 2a + 3b + 6c = 0
• This implies that the sum of the coefficients of x in the quadratic equation is zero.
• For a quadratic equation ax^2 + bx + c = 0 to have real roots, the discriminant (b^2 - 4ac) must be greater than or equal to zero.
• The discriminant for this equation is b^2 - 4ac = (3^2 - 4*2*6) = 9 - 48 = -39.
• Since the discriminant is negative, the roots of the equation are complex.
• Complex roots always come in conjugate pairs.
• Therefore, the roots of the given equation will lie in the interval where the real part is the same and the imaginary part is of opposite sign.
• The roots will not lie within a specific interval on the real number line but rather in the complex plane.
Thus, the roots of the equation ax^2 + bx + c will be complex and will not lie within a specific interval on the real number line.
• Given equation: 2a + 3b + 6c = 0
• This implies that the sum of the coefficients of x in the quadratic equation is zero.
• For a quadratic equation ax^2 + bx + c = 0 to have real roots, the discriminant (b^2 - 4ac) must be greater than or equal to zero.
• The discriminant for this equation is b^2 - 4ac = (3^2 - 4*2*6) = 9 - 48 = -39.
• Since the discriminant is negative, the roots of the equation are complex.
• Complex roots always come in conjugate pairs.
• Therefore, the roots of the given equation will lie in the interval where the real part is the same and the imaginary part is of opposite sign.
• The roots will not lie within a specific interval on the real number line but rather in the complex plane.
Thus, the roots of the equation ax^2 + bx + c will be complex and will not lie within a specific interval on the real number line.
Community Answer
If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation li...
Zero to 1
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is?
Question Description
If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is?.
If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is?.
Solutions for If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? defined & explained in the simplest way possible. Besides giving the explanation of
If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is?, a detailed solution for If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? has been provided alongside types of If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? theory, EduRev gives you an
ample number of questions to practice If ax2+bx+c,a,b,care real, if 2a+3b+6c=0,then roots of the equation lies in the interval is? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup