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The solution set of the equation 4sin q . cos q – 2 cos q – 2
sin q + 
= 0 in the interval (0, 2p) is
sin q + = 0 in the interval (0, 2p) is- a)
- b)
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The solution set of the equation 4sin q . cos q –2 cos q –...
4sinqcosq - 2cosq - 2√3sinq + √3 = 0
2cosq(2sinq - 1) - √3(2sinq - 1) = 0
(2sinq - 1) (2cosq - √3) = 0
sinq = 1/2 , cosq = √3/2
q = π/6, 5π/6. , q = π/6, 11π/6
q = {π/6 , 5π/6, 11π/6}
2cosq(2sinq - 1) - √3(2sinq - 1) = 0
(2sinq - 1) (2cosq - √3) = 0
sinq = 1/2 , cosq = √3/2
q = π/6, 5π/6. , q = π/6, 11π/6
q = {π/6 , 5π/6, 11π/6}
Most Upvoted Answer
The solution set of the equation 4sin q . cos q –2 cos q –...
4sinqcosq - 2cosq - 2√3sinq + √3 = 0
2cosq(2sinq - 1) - √3(2sinq - 1) = 0
(2sinq - 1) (2cosq - √3) = 0
sinq = 1/2 , cosq = √3/2
q = π/6, 5π/6. , q = π/6, 11π/6
q = {π/6 , 5π/6, 11π/6}
2cosq(2sinq - 1) - √3(2sinq - 1) = 0
(2sinq - 1) (2cosq - √3) = 0
sinq = 1/2 , cosq = √3/2
q = π/6, 5π/6. , q = π/6, 11π/6
q = {π/6 , 5π/6, 11π/6}
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Community Answer
The solution set of the equation 4sin q . cos q –2 cos q –...
4sinqcosq - 2cosq - 2√3sinq + √3 = 0
2cosq(2sinq - 1) - √3(2sinq - 1) = 0
(2sinq - 1) (2cosq - √3) = 0
sinq = 1/2 , cosq = √3/2
q = π/6, 5π/6. , q = π/6, 11π/6
q = {π/6 , 5π/6, 11π/6}
2cosq(2sinq - 1) - √3(2sinq - 1) = 0
(2sinq - 1) (2cosq - √3) = 0
sinq = 1/2 , cosq = √3/2
q = π/6, 5π/6. , q = π/6, 11π/6
q = {π/6 , 5π/6, 11π/6}
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The solution set of the equation 4sin q . cos q –2 cos q –2sin q += 0 in the interval (0, 2p) isa)b)c)d)Correct answer is option 'D'. Can you explain this answer?
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