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A 0.6025g sample of a chloride salt was dissolved in water and the chloride precipitated by adding excess silver nitrate. The precipitate of silver chloride was filtered, washed, dried and found to weigh 0.7134g. Calculate the percentage of chloride (Cl) in the sample.?
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A 0.6025g sample of a chloride salt was dissolved in water and the chl...
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A 0.6025g sample of a chloride salt was dissolved in water and the chl...
Given:
- Mass of chloride salt = 0.6025g
- Mass of silver chloride precipitate = 0.7134g

Goal:
- Calculate the percentage of chloride (Cl) in the sample.

Procedure:
1. Calculate the mass of chloride in the silver chloride precipitate.
2. Calculate the molar mass of silver chloride.
3. Use the molar mass to calculate the moles of silver chloride.
4. Calculate the moles of chloride in the silver chloride.
5. Calculate the percentage of chloride in the sample.

Calculations:

1. Calculate the mass of chloride in the silver chloride precipitate:
- Mass of silver chloride precipitate = 0.7134g

2. Calculate the molar mass of silver chloride:
- The molar mass of silver chloride (AgCl) is the sum of the atomic masses of silver (Ag) and chlorine (Cl).
- The atomic mass of Ag = 107.87 g/mol
- The atomic mass of Cl = 35.45 g/mol
- Molar mass of AgCl = 107.87 + 35.45 = 143.32 g/mol

3. Use the molar mass to calculate the moles of silver chloride:
- Moles of silver chloride = Mass of silver chloride precipitate / Molar mass of AgCl
- Moles of silver chloride = 0.7134g / 143.32 g/mol = 0.00498 mol

4. Calculate the moles of chloride in the silver chloride:
- Since silver chloride (AgCl) has a 1:1 ratio of silver (Ag) to chloride (Cl), the moles of chloride are the same as the moles of silver chloride.
- Moles of chloride = 0.00498 mol

5. Calculate the percentage of chloride in the sample:
- Percentage of chloride = (Moles of chloride / Total moles of the sample) x 100
- Total moles of the sample = Mass of chloride salt / Molar mass of chloride salt
- The molar mass of chloride (Cl) is 35.45 g/mol (since chlorine is a diatomic molecule, Cl2)
- Total moles of the sample = 0.6025g / 35.45 g/mol = 0.017 mol

- Percentage of chloride = (0.00498 mol / 0.017 mol) x 100 = 29.29%

Answer:
The percentage of chloride (Cl) in the sample is 29.29%.
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A 0.6025g sample of a chloride salt was dissolved in water and the chloride precipitated by adding excess silver nitrate. The precipitate of silver chloride was filtered, washed, dried and found to weigh 0.7134g. Calculate the percentage of chloride (Cl) in the sample.?
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A 0.6025g sample of a chloride salt was dissolved in water and the chloride precipitated by adding excess silver nitrate. The precipitate of silver chloride was filtered, washed, dried and found to weigh 0.7134g. Calculate the percentage of chloride (Cl) in the sample.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 0.6025g sample of a chloride salt was dissolved in water and the chloride precipitated by adding excess silver nitrate. The precipitate of silver chloride was filtered, washed, dried and found to weigh 0.7134g. Calculate the percentage of chloride (Cl) in the sample.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.6025g sample of a chloride salt was dissolved in water and the chloride precipitated by adding excess silver nitrate. The precipitate of silver chloride was filtered, washed, dried and found to weigh 0.7134g. Calculate the percentage of chloride (Cl) in the sample.?.
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