The science lecture theatre of a college is 10 m wide and has a door a...
Problem Statement
A science teacher enters a science lecture theatre of a college through a door at a corner at 12.00 noon and makes 8 rounds along the 10 m wall back and forth during the period and finally leaves the class room at 12.40 p.m. through the same door. Compute the average speed and average velocity of science teacher.
Solution
Understanding the Problem
Before we begin solving the problem, let's understand some basic concepts:
- Speed: The distance covered by an object in a given time interval is called its speed. It is measured in m/s or km/hr.
- Velocity: Velocity is the speed of an object in a particular direction. It is measured in m/s or km/hr.
Calculating Distance Covered
The width of the science lecture theatre is given as 10 m. The teacher makes 8 rounds along this wall back and forth. Therefore, the distance covered by the teacher can be calculated as follows:
Distance covered = 2 x 10 m x 8 = 160 m
Calculating Time Taken
The teacher enters the class at 12.00 noon and leaves at 12.40 p.m. Therefore, the time taken by the teacher can be calculated as follows:
Time taken = 12.40 p.m. - 12.00 noon = 40 minutes = 2400 seconds
Calculating Average Speed
The average speed of the teacher can be calculated as follows:
Average speed = Distance covered ÷ Time taken
Average speed = 160 m ÷ 2400 s
Average speed = 0.067 m/s
Calculating Average Velocity
The teacher enters and leaves the classroom through the same door. Therefore, the displacement of the teacher is zero. Hence, the average velocity of the teacher is also zero.
Conclusion
Therefore, the average speed of the teacher is 0.067 m/s and the average velocity is zero.