Question Description
A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer?.

Solutions for A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop in fig. The current induced in the loop isa)BIu/R clockwiseb)BIu/R anticlockwisec)2BIu/R anticlockwised)zeroCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.