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For flow over a flat plate the hydrodynamic boundary layer thicknessis 0.5 mm. The dynamic viscosity is 25 × 10-6 Pa s, specific heat is 2.0kJ/(kgK) and thermal conductivity is 0.05 W/(m–K). The thermal boundary layer thickness would be:  
  • a)
    0.1 mm
  • b)
    0.5 mm
  • c)
    1 mm
  • d)
    2 mm
Correct answer is option 'B'. Can you explain this answer?
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For flow over a flat plate the hydrodynamic boundary layer thicknessis...
Ans. (b)
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For flow over a flat plate the hydrodynamic boundary layer thicknessis...
Find prandtl number Pr =uc/k=1 (Pr)^0.33=velocity boundary layer/ thermal boundary layer
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For flow over a flat plate the hydrodynamic boundary layer thicknessis...
Calculation of Thermal Boundary Layer Thickness:
1. The thermal boundary layer thickness can be calculated using the Prandtl number, which is the ratio of momentum diffusivity to thermal diffusivity.
2. Prandtl number (Pr) is given by the formula: Pr = μ * Cp / k, where μ is the dynamic viscosity, Cp is the specific heat, and k is the thermal conductivity.
3. Substituting the given values, we get: Pr = (25 * 10^-6 * 2) / 0.05 = 1.
4. For flow over a flat plate, the thermal boundary layer thickness is equal to the hydrodynamic boundary layer thickness multiplied by the Prandtl number.
5. Therefore, the thermal boundary layer thickness = 0.5 mm * 1 = 0.5 mm.
Therefore, the correct answer is option 'B' - 0.5 mm.
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For flow over a flat plate the hydrodynamic boundary layer thicknessis 0.5 mm. The dynamic viscosity is 25 × 10-6 Pa s, specific heat is 2.0kJ/(kgK) and thermal conductivity is 0.05 W/(m–K). The thermal boundary layer thickness would be:a)0.1 mmb)0.5 mmc)1 mmd)2 mmCorrect answer is option 'B'. Can you explain this answer?
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