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Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:
1. Electrical conductivity of materials
2. Pelti er coefficie nt
3. Seeb eck coefficie nt
4. Temperature at cold and hot junctions
5. Thermal conductivity of materials.
Of these statements:
[IES-1997]
- a)1, 3, 4 and 5 are correct
- b)1, 2, 3 and 5 are correct
- c)1, 2, 4 and 5 are correct
- d)2, 3, 4 and 5 are correct
Correct answer is option 'C'. Can you explain this answer?
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Consider the following statements: In the thermoelectric refrigeration...
Thermoelectric Refrigeration and Coefficient of Performance
Thermoelectric refrigeration is a process of cooling that uses the Peltier effect to transfer heat. The coefficient of performance (COP) is a measure of the efficiency of the refrigeration process. The following statements explain the factors that affect the COP in thermoelectric refrigeration.
1. Electrical conductivity of materials
The electrical conductivity of materials used in thermoelectric refrigeration affects the COP. Materials with high electrical conductivity and low thermal conductivity are preferred for thermoelectric cooling applications.
2. Peltier coefficient
The Peltier coefficient is a thermoelectric property of materials that determines the amount of heat absorbed or released when an electric current is passed through them. The higher the Peltier coefficient, the greater the cooling effect.
3. Seebeck coefficient
The Seebeck coefficient is another thermoelectric property that determines the amount of electrical voltage generated when a temperature gradient is applied across a material. Higher Seebeck coefficient materials are preferred for thermoelectric cooling applications.
4. Temperature at cold and hot junctions
The temperature at the cold and hot junctions of the thermoelectric cooler affects the COP. Lower temperatures at the cold junction and higher temperatures at the hot junction result in a higher COP.
5. Thermal conductivity of materials
Thermal conductivity is the ability of a material to conduct heat. Materials with low thermal conductivity are preferred for thermoelectric cooling applications. This is because low thermal conductivity materials reduce the heat transfer from the cold side to the hot side, resulting in a higher COP.
Conclusion
In summary, the coefficient of performance in thermoelectric refrigeration is affected by various factors including the electrical conductivity, Peltier and Seebeck coefficients, temperature at cold and hot junctions, and thermal conductivity of materials. Therefore, selecting the appropriate materials and operating conditions is critical for achieving high COP and efficient thermoelectric refrigeration.
Thermoelectric refrigeration is a process of cooling that uses the Peltier effect to transfer heat. The coefficient of performance (COP) is a measure of the efficiency of the refrigeration process. The following statements explain the factors that affect the COP in thermoelectric refrigeration.
1. Electrical conductivity of materials
The electrical conductivity of materials used in thermoelectric refrigeration affects the COP. Materials with high electrical conductivity and low thermal conductivity are preferred for thermoelectric cooling applications.
2. Peltier coefficient
The Peltier coefficient is a thermoelectric property of materials that determines the amount of heat absorbed or released when an electric current is passed through them. The higher the Peltier coefficient, the greater the cooling effect.
3. Seebeck coefficient
The Seebeck coefficient is another thermoelectric property that determines the amount of electrical voltage generated when a temperature gradient is applied across a material. Higher Seebeck coefficient materials are preferred for thermoelectric cooling applications.
4. Temperature at cold and hot junctions
The temperature at the cold and hot junctions of the thermoelectric cooler affects the COP. Lower temperatures at the cold junction and higher temperatures at the hot junction result in a higher COP.
5. Thermal conductivity of materials
Thermal conductivity is the ability of a material to conduct heat. Materials with low thermal conductivity are preferred for thermoelectric cooling applications. This is because low thermal conductivity materials reduce the heat transfer from the cold side to the hot side, resulting in a higher COP.
Conclusion
In summary, the coefficient of performance in thermoelectric refrigeration is affected by various factors including the electrical conductivity, Peltier and Seebeck coefficients, temperature at cold and hot junctions, and thermal conductivity of materials. Therefore, selecting the appropriate materials and operating conditions is critical for achieving high COP and efficient thermoelectric refrigeration.
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Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:1. Electrical conductivity of materials 2. Pelti er coefficie nt 3. Seeb eck coefficie nt 4. Temperature at cold and hot junctions 5. Thermal conductivity of materials.Of these statements:[IES-1997]a)1, 3, 4 and 5 are correctb)1, 2, 3 and 5 are correctc)1, 2, 4 and 5 are correctd)2, 3, 4 and 5 are correctCorrect answer is option 'C'. Can you explain this answer?
Question Description
Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:1. Electrical conductivity of materials 2. Pelti er coefficie nt 3. Seeb eck coefficie nt 4. Temperature at cold and hot junctions 5. Thermal conductivity of materials.Of these statements:[IES-1997]a)1, 3, 4 and 5 are correctb)1, 2, 3 and 5 are correctc)1, 2, 4 and 5 are correctd)2, 3, 4 and 5 are correctCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:1. Electrical conductivity of materials 2. Pelti er coefficie nt 3. Seeb eck coefficie nt 4. Temperature at cold and hot junctions 5. Thermal conductivity of materials.Of these statements:[IES-1997]a)1, 3, 4 and 5 are correctb)1, 2, 3 and 5 are correctc)1, 2, 4 and 5 are correctd)2, 3, 4 and 5 are correctCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:1. Electrical conductivity of materials 2. Pelti er coefficie nt 3. Seeb eck coefficie nt 4. Temperature at cold and hot junctions 5. Thermal conductivity of materials.Of these statements:[IES-1997]a)1, 3, 4 and 5 are correctb)1, 2, 3 and 5 are correctc)1, 2, 4 and 5 are correctd)2, 3, 4 and 5 are correctCorrect answer is option 'C'. Can you explain this answer?.
Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:1. Electrical conductivity of materials 2. Pelti er coefficie nt 3. Seeb eck coefficie nt 4. Temperature at cold and hot junctions 5. Thermal conductivity of materials.Of these statements:[IES-1997]a)1, 3, 4 and 5 are correctb)1, 2, 3 and 5 are correctc)1, 2, 4 and 5 are correctd)2, 3, 4 and 5 are correctCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:1. Electrical conductivity of materials 2. Pelti er coefficie nt 3. Seeb eck coefficie nt 4. Temperature at cold and hot junctions 5. Thermal conductivity of materials.Of these statements:[IES-1997]a)1, 3, 4 and 5 are correctb)1, 2, 3 and 5 are correctc)1, 2, 4 and 5 are correctd)2, 3, 4 and 5 are correctCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:1. Electrical conductivity of materials 2. Pelti er coefficie nt 3. Seeb eck coefficie nt 4. Temperature at cold and hot junctions 5. Thermal conductivity of materials.Of these statements:[IES-1997]a)1, 3, 4 and 5 are correctb)1, 2, 3 and 5 are correctc)1, 2, 4 and 5 are correctd)2, 3, 4 and 5 are correctCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Consider the following statements: In the thermoelectric refrigeration, the coefficient of performance is a function of:1. Electrical conductivity of materials 2. Pelti er coefficie nt 3. Seeb eck coefficie nt 4. Temperature at cold and hot junctions 5. Thermal conductivity of materials.Of these statements:[IES-1997]a)1, 3, 4 and 5 are correctb)1, 2, 3 and 5 are correctc)1, 2, 4 and 5 are correctd)2, 3, 4 and 5 are correctCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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