**Volume of the Block**

To find the volume of the block, we need to multiply its length, breadth, and height.

Given measurements:
- Length = 1.37 cm
- Breadth = 4.11 cm
- Height = 2.56 cm

Therefore, the volume of the block can be calculated as follows:

Volume = Length × Breadth × Height

Volume = 1.37 cm × 4.11 cm × 2.56 cm

Volume = 14.121 cm³ (approximately)

**Error in Vernier Calipers**

Vernier calipers are precision measuring instruments that can provide accurate measurements up to a certain level of precision. However, there is always a possibility of error in any measurement, including those obtained using Vernier calipers.

The error in Vernier calipers can arise due to various factors such as parallax error, improper zero adjustment, or manufacturing defects. It is important to consider the error in the measured values while calculating the volume of the block.

**Error Calculation**

To calculate the error in the volume of the block, we need to consider the errors in each measured value and their impact on the final result. Let's assume the errors in the measured values are as follows:

Error in Length = ±0.01 cm
Error in Breadth = ±0.01 cm
Error in Height = ±0.01 cm

The error in volume can be calculated using the formula:

Error in Volume = Volume × √((Error in Length/Length)² + (Error in Breadth/Breadth)² + (Error in Height/Height)²)

Error in Volume = 14.121 cm³ × √((0.01 cm/1.37 cm)² + (0.01 cm/4.11 cm)² + (0.01 cm/2.56 cm)²)

Error in Volume = 14.121 cm³ × √(0.0073 + 0.0006 + 0.0015)

Error in Volume = 14.121 cm³ × √0.0094

Error in Volume = 14.121 cm³ × 0.097 cm

Error in Volume = 1.369 cm³ (approximately)

**Conclusion**

Therefore, the volume of the block is approximately 14.121 cm³, with an error of ±1.369 cm³. It is important to consider the error in measurements to ensure the accuracy and precision of the final result.

Volume = L * b * h#v = 1.37 cm * 4.11 cm * 2.56 cm = 14.42 cm ^3___ Relative error = dv / v___dv/ v = dL / L + db / b + dh/ h___ ##Note:: least count of vernier caliper is 1 mm...hence it's possible least error is 1mm or 0.1 cm_______dv/ v = 0.1 / 1.37 + 0.1 / 4.11 + 0.1 / 2.56 _____________ dv = [ 0.1 / 1.37 + 0.1 / 4.11 + 0.1 / 2.56 ] v __________dv = (1.442 / 1.37 ) + (1.442 / 4.11) + (1.442 / 2.56 ) _______ dv = 1.96 cm^3_______Therefore Volume of Block is ==> 14.42 cm ^3 And error is ==> 1.96cm^3_____(V + _ dv ) = ( 14.42 cm ^3 + _ 1.96 cm ^3 )...