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A ball hits a wall horizontally at 6 m per second it rebounds horizontally 4.4 M per second A ball is in contact with the wall for 0.04 second what is the acceleration of the ball?
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A ball hits a wall horizontally at 6 m per second it rebounds horizont...

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A ball hits a wall horizontally at 6 m per second it rebounds horizont...
Given:
Initial velocity of the ball, u = 6 m/s
Final velocity of the ball, v = -4.4 m/s (negative sign indicates the ball is rebounding in the opposite direction)
Time of contact with the wall, t = 0.04 s

To find:
Acceleration of the ball, a

Formula:
The formula to calculate acceleration is:
a = (v - u) / t

Calculation:
Substituting the given values into the formula, we get:
a = (-4.4 - 6) / 0.04

Simplifying the expression:
a = (-10.4) / 0.04

Dividing -10.4 by 0.04, we get:
a = -260 m/s²

Explanation:
When a ball hits a wall horizontally and rebounds horizontally, it experiences a change in velocity. The acceleration of the ball can be calculated using the formula: a = (v - u) / t, where v is the final velocity, u is the initial velocity, and t is the time of contact with the wall.

In this case, the initial velocity of the ball is given as 6 m/s, and the final velocity is -4.4 m/s (negative sign indicates the ball is rebounding in the opposite direction). The time of contact with the wall is given as 0.04 seconds.

Substituting these values into the formula, we can calculate the acceleration of the ball. By simplifying the expression, we find that the acceleration is -260 m/s².

Therefore, the acceleration of the ball is -260 m/s². The negative sign indicates that the ball is decelerating or slowing down during the contact with the wall.
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