If the point ( 3,4 )lies on the graph of the equation 3y = ax+7 find t...
Given:
The point (3,4) lies on the graph of the equation 3y = ax + 7.
To Find:
The value of A.
Solution:
To find the value of A, we need to substitute the coordinates of the given point (3,4) into the equation 3y = ax + 7 and solve for A.
Step 1: Substitute the coordinates of the given point into the equation.
In this case, the x-coordinate is 3 and the y-coordinate is 4. So, we substitute these values into the equation:
3(4) = a(3) + 7
Simplifying the equation, we get:
12 = 3a + 7
Step 2: Solve the equation for A.
To solve the equation, we need to isolate the term containing A on one side of the equation.
Subtracting 7 from both sides of the equation, we have:
12 - 7 = 3a
5 = 3a
Now, we divide both sides of the equation by 3 to solve for A:
5/3 = a
Step 3: Determine the value of A.
The value of A is 5/3 or 1.67.
Conclusion:
The value of A in the equation 3y = ax + 7, given that the point (3,4) lies on the graph, is 5/3 or 1.67.
If the point ( 3,4 )lies on the graph of the equation 3y = ax+7 find t...
Here,x=3 and y=4...So,we have to put the value of x and y in the equation like this=> ..3y=ax+7 => 3(4)=a(3)+7 =>12=3a+7 =>12-7=3a =>5=3a or a=5/3... Now, Verification... =>3(4)=(5/3)×(3)+7 =>12=5+7 =>12=12.. =>L.H.S = R.H.S Verified..
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