The angles of a quardilateral are in A.P. and greatest is double the l...
We know that the sum of all interior angles of a quadrilateral is 360
let x, x + d, x + 2d, x + 3d be the angles
x + (x + d) + (x + 2d) + (x + 3d) = 360
4x + 6d = 360
also the greatesr angle x + 3d = 2x
x = 3d
Substitute this value of x in equation 1
4(3d) + 6d = 360
12d + 6d = 360
18d = 360
d = 20 degrees
x = 60 degree or pi/3 radians (least angle)
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The angles of a quardilateral are in A.P. and greatest is double the l...
Given Information:
- Angles of a quadrilateral are in A.P.
- The greatest angle is double the least angle.
Explanation:
- Let the four angles be A, B, C, and D.
- Since the angles are in A.P., we can represent them as A, A + d, A + 2d, and A + 3d.
- Given that the greatest angle is double the least angle, we have A + 3d = 2A.
- Solving the equation, we get A = 3d.
Calculating the least angle:
- Substitute A = 3d in the A.P. sequence: A, A + d, A + 2d, and A + 3d.
- The angles become 3d, 4d, 5d, and 6d.
- The least angle is 3d.
Converting to radians:
- To find the least angle in radians, we know that 180 degrees = π radians.
- So, the least angle in radians = 3d * π / 180.
Final Answer:
- The least angle in radians is 3d * π / 180.
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