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An object starting from rest travelled 20 in the first two seconds and 160m in next 4 seconds.What will be the velocity after 7seconds?
Verified Answer
An object starting from rest travelled 20 in the first two seconds and...
Given:
Initial velocity = u =0m/s
Distance travelled =S=20m
time =t=2sec.
From second equation of motion:
S=ut + 1/2 at^2
20= 0*2+ 1/2a2^2
20=2a
a=10m/s^2
velocity at the end of 2sec:
V=u+at
=0+10*2
V=20m/s
After 4sec, it covers a distance of 160m
so,
160=20*4+1/2(a^1)4^2
160=80+2a
8a^1=80
a^1=10m/s^2
It shows acceleration is uniform.
So, velocity at end of 7 sec from start:
V=u+at
= 0 + 10*7
=70m/s
∴the velocity after 7 sec from the start is 70m/s
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An object starting from rest travelled 20 in the first two seconds and 160m in next 4 seconds.What will be the velocity after 7seconds?
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