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Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1
H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 and ΔfH° (CxH4) = - 100 kcal mol-1
Q. What is the value of x?
Correct answer is '3'. Can you explain this answer?
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Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - ...
To find the value of x in the compound CXH4, we need to use the given enthalpy values of combustion. Enthalpy of combustion is the heat released when one mole of a substance undergoes complete combustion with oxygen.
Given data:
Enthalpy of combustion of carbon (s) = -94 kcal mol-1
Enthalpy of combustion of H2(g) = -68 kcal mol-1
Enthalpy of formation of CXH4 = -318 kcal mol-1
Enthalpy of formation of H2O(g) = -100 kcal mol-1
We can break down the combustion of CXH4 into the combustion of its individual elements, carbon and hydrogen, and then sum up the enthalpy changes.
The balanced equation for the combustion of CXH4 is:
CXH4 + (4+x)/2 O2 → x CO2 + (2+x)/2 H2O
- The enthalpy change for the combustion of CXH4 is -318 kcal mol-1.
- The enthalpy change for the combustion of carbon is -94 kcal mol-1.
- The enthalpy change for the combustion of hydrogen is -68 kcal mol-1.
Summing up these enthalpy changes, we get:
-318 kcal mol-1 = x(-94 kcal mol-1) + [(4+x)/2](-68 kcal mol-1) + [(2+x)/2](-100 kcal mol-1)
Simplifying the equation:
-318 = -94x - 34 - 34x - 50 - 50x
-318 = -178x - 84
Adding 84 to both sides:
-234 = -178x
Dividing by -178:
x = 234/178
x ≈ 1.31
Therefore, the value of x is approximately 1.31, not 3 as stated in the correct answer.
It seems there may be an error in the given information or the correct answer provided. Please double-check the data to ensure accuracy.
Given data:
Enthalpy of combustion of carbon (s) = -94 kcal mol-1
Enthalpy of combustion of H2(g) = -68 kcal mol-1
Enthalpy of formation of CXH4 = -318 kcal mol-1
Enthalpy of formation of H2O(g) = -100 kcal mol-1
We can break down the combustion of CXH4 into the combustion of its individual elements, carbon and hydrogen, and then sum up the enthalpy changes.
The balanced equation for the combustion of CXH4 is:
CXH4 + (4+x)/2 O2 → x CO2 + (2+x)/2 H2O
- The enthalpy change for the combustion of CXH4 is -318 kcal mol-1.
- The enthalpy change for the combustion of carbon is -94 kcal mol-1.
- The enthalpy change for the combustion of hydrogen is -68 kcal mol-1.
Summing up these enthalpy changes, we get:
-318 kcal mol-1 = x(-94 kcal mol-1) + [(4+x)/2](-68 kcal mol-1) + [(2+x)/2](-100 kcal mol-1)
Simplifying the equation:
-318 = -94x - 34 - 34x - 50 - 50x
-318 = -178x - 84
Adding 84 to both sides:
-234 = -178x
Dividing by -178:
x = 234/178
x ≈ 1.31
Therefore, the value of x is approximately 1.31, not 3 as stated in the correct answer.
It seems there may be an error in the given information or the correct answer provided. Please double-check the data to ensure accuracy.
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Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer?
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Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer?.
Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer?.
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Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer?, a detailed solution for Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer? has been provided alongside types of Given, enthalpy of combustion of carbon (s) = -94 kcal mol-1H2(g) = - 68 kcal mol-1 and CXH4 = - 318 kcal mol-1 andΔfH° (CxH4) = - 100 kcal mol-1Q. What is the value of x?Correct answer is '3'. Can you explain this answer? theory, EduRev gives you an
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