All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
Class 12 Exam  >  Class 12 Questions  >  A galvanometer with a coil of resistance 40 o... Start Learning for Free
SaveJoin the Discussion on the App
A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A?
Clear all your Class 12 doubts with EduRev
Verified Answer
A galvanometer with a coil of resistance 40 ohm gives a full scale def...
Given :
G = 40 Ω
Ig = 5 mA = 5 x 10^-3 A
I = 5 A
To Find :
S = ?

This question is part of UPSC exam. View all Class 12 courses
Most Upvoted Answer
A galvanometer with a coil of resistance 40 ohm gives a full scale def...
Converting a Galvanometer into an Ammeter

To convert a galvanometer into an ammeter with a range of 0-5A, we need to add a shunt resistor to the galvanometer circuit. The shunt resistor will bypass most of the current, allowing only a fraction of it to pass through the galvanometer.

Calculating the Shunt Resistor Value:
To determine the value of the shunt resistor, we need to consider the desired full-scale deflection current and the resistance of the galvanometer coil.

Given:
- Resistance of the galvanometer coil (Rg) = 40 ohm
- Full-scale deflection current (Ig) = 5mA

Using Ohm's Law, we can calculate the resistance of the shunt resistor (Rs) that will allow the desired full-scale deflection current to pass through the galvanometer.

Ohm's Law: V = IR

Step 1:
Calculate the voltage drop across the galvanometer coil at full-scale deflection.
Vg = Ig * Rg
Vg = 5mA * 40 ohm
Vg = 0.2V

Step 2:
Determine the desired full-scale deflection current for the ammeter.
Im = 5A

Step 3:
Calculate the resistance of the shunt resistor required to allow the desired full-scale deflection current to pass through the galvanometer.
Rs = Vg / Im
Rs = 0.2V / 5A
Rs = 0.04 ohm

Adding the Shunt Resistor:
Once the value of the shunt resistor (Rs) is determined, it needs to be connected in parallel with the galvanometer. The shunt resistor will provide a low-resistance path for most of the current, allowing only a fraction of it to pass through the galvanometer coil.

Important Considerations:
- The shunt resistor should have a very low resistance compared to the galvanometer coil to ensure most of the current bypasses the galvanometer.
- The shunt resistor should be designed to handle the maximum current that may flow through the ammeter. In this case, it should be able to handle up to 5A.
- It is recommended to use precision resistors to ensure accurate current measurement.
- The shunt resistor should be connected in parallel with the galvanometer, ensuring proper polarity and connection.

Summary:
In summary, to convert a galvanometer into an ammeter with a range of 0-5A, a shunt resistor is added in parallel with the galvanometer. The value of the shunt resistor is calculated based on the desired full-scale deflection current and the resistance of the galvanometer coil. The shunt resistor provides a low-resistance path for most of the current, allowing only a fraction of it to pass through the galvanometer, thereby enabling accurate current measurement.
Explore Courses for Class 12 exam

Similar Class 12 Doubts

Read the following text and answer the following questions on the basis of the same: Galvanometer can sense/measure current. Improved mirror galvanometer was developed by William Thomson, later to become Lord Kelvin, in 1858. Thomson intended the instrument to read weak signal currents on very long submarine telegraph cables. The fundamental problems of transmitting/ receiving a signal through a lengthy submarine cable was that the electrical current tended to be very low (as little as 1/100,000th of a standard light bul b). So, it was very difficult to detect it. To solve the problem it was thought that larger amount of electric current would be sent through the line. But Thomson had a different approach. He thought the best response was to devise a device that could read faint signals. The galvanometer, first invented in 1802, was a means of detecting electric current. It consisted of a needle that was deflected by the magnetic field created by the electric current. But the galvanometers of the day couldn't detect the weak signals that came through a long underwater cable. But the improved version of galvanometer was highly sensitive to detect the lowest current. The mirror galvanometer consists of a long fine coil of silk-covered copper wire. In the heart of that coil, within a little air-chamber, a small round mirror is hung by a single fibre of floss silk, with four tiny magnets cemented to its back. A beam of light is thrown from a lamp upon the mirror, and reflected by it upon a white screen or scale a few feet distant, where it forms a bright spot of light; when there is no current on the instrument, the spot of light remains stationary at the zero position on the screen; but the instant a current traverses the long wire of the coil, the suspended magnets twist themselves horizontally out of their former position, the mirror is inclined with them, and the beam of light is deflected along the screen to one side or the other, according to the nature of the current. If a positive electric current gives a deflection to the right of zero, a negative current will give a deflection to the left of zero, and vice versa. The air in the little chamber surrounding the mirror is compressed, so as to act like a cushion, and deaden the movements of the mirror; the mirror is thus prevented from idly swinging about at each deflections.The basic principle of galvanometer is

Read the following text and answer the following questions on the basis of the same: Galvanometer can sense/measure current. Improved mirror galvanometer was developed by William Thomson, later to become Lord Kelvin, in 1858. Thomson intended the instrument to read weak signal currents on very long submarine telegraph cables. The fundamental problems of transmitting/ receiving a signal through a lengthy submarine cable was that the electrical current tended to be very low (as little as 1/100,000th of a standard light bul b). So, it was very difficult to detect it. To solve the problem it was thought that larger amount of electric current would be sent through the line. But Thomson had a different approach. He thought the best response was to devise a device that could read faint signals. The galvanometer, first invented in 1802, was a means of detecting electric current. It consisted of a needle that was deflected by the magnetic field created by the electric current. But the galvanometers of the day couldn't detect the weak signals that came through a long underwater cable. But the improved version of galvanometer was highly sensitive to detect the lowest current. The mirror galvanometer consists of a long fine coil of silk-covered copper wire. In the heart of that coil, within a little air-chamber, a small round mirror is hung by a single fibre of floss silk, with four tiny magnets cemented to its back. A beam of light is thrown from a lamp upon the mirror, and reflected by it upon a white screen or scale a few feet distant, where it forms a bright spot of light; when there is no current on the instrument, the spot of light remains stationary at the zero position on the screen; but the instant a current traverses the long wire of the coil, the suspended magnets twist themselves horizontally out of their former position, the mirror is inclined with them, and the beam of light is deflected along the screen to one side or the other, according to the nature of the current. If a positive electric current gives a deflection to the right of zero, a negative current will give a deflection to the left of zero, and vice versa. The air in the little chamber surrounding the mirror is compressed, so as to act like a cushion, and deaden the movements of the mirror; the mirror is thus prevented from idly swinging about at each deflections.Mirror galvanometer was primarily used to

Read the following text and answer the following questions on the basis of the same:Galvanometer can sense/measure current. Improved mirror galvanometer was developed by William Thomson, later to become Lord Kelvin, in 1858. Thomson intended the instrument to read weak signal currents on very long submarine telegraph cables. The fundamental problems of transmitting/ receiving a signal through a lengthy submarine cable was that the electrical current tended to be very low (as little as 1/100,000th of a standard light bul b). So, it was very difficult to detect it. To solve the problem it was thought that larger amount of electric current would be sent through the line. But Thomson had a different approach. He thought the best response was to devise a device that could read faint signals. The galvanometer, first invented in 1802, was a means of detecting electric current. It consisted of a needle that was deflected by the magnetic field created by the electric current. But the galvanometers of the day couldn't detect the weak signals that came through a long underwater cable. But the improved version of galvanometer was highly sensitive to detect the lowest current. The mirror galvanometer consists of a long fine coil of silk-covered copper wire. In the heart of that coil, within a little air-chamber, a small round mirror is hung by a single fibre of floss silk, with four tiny magnets cemented to its back. A beam of light is thrown from a lamp upon the mirror, and reflected by it upon a white screen or scale a few feet distant, where it forms a bright spot of light; when there is no current on the instrument, the spot of light remains stationary at the zero position on the screen; but the instant a current traverses the long wire of the coil, the suspended magnets twist themselves horizontally out of their former position, the mirror is inclined with them, and the beam of light is deflected along the screen to one side or the other, according to the nature of the current. If a positive electric current gives a deflection to the right of zero, a negative current will give a deflection to the left of zero, and vice versa. The air in the little chamber surrounding the mirror is compressed, so as to act like a cushion, and deaden the movements of the mirror; the mirror is thus prevented from idly swinging about at each deflections.Improved mirror galvanometer was developed by

A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A?
Question Description
A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A?.
Solutions for A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A? defined & explained in the simplest way possible. Besides giving the explanation of A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A?, a detailed solution for A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A? has been provided alongside types of A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A? theory, EduRev gives you an ample number of questions to practice A galvanometer with a coil of resistance 40 ohm gives a full scale deflation for a current of 5mA . How will you convert it into an a meter of range 0-5A? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup