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A proton of 300 nm is absorbed by a gas and then re- mitted photons has wave length 496 nm ,the wave length of second re emitted photon is ?
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A proton of 300 nm is absorbed by a gas and then re- mitted photons ha...

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A proton of 300 nm is absorbed by a gas and then re- mitted photons ha...
Explanation:

Initial Absorption and Re-emission:
- A proton with a wavelength of 300 nm is absorbed by a gas.
- The gas then re-emits photons with a wavelength of 496 nm.

Calculating Energy Difference:
- To find the wavelength of the second re-emitted photon, we need to calculate the energy difference between the absorbed and re-emitted photons.
- Using the formula E = hc/λ, where E is energy, h is Planck's constant, c is the speed of light, and λ is the wavelength.

Energy Conservation:
- Energy is conserved in the process of absorption and re-emission, so the energy of the second re-emitted photon will be the same as the energy of the absorbed proton.

Calculating Second Re-emitted Wavelength:
- Using the energy calculated earlier, we can find the wavelength of the second re-emitted photon by rearranging the formula E = hc/λ.

Final Answer:
- By applying the energy conservation principle and the formula for calculating wavelength from energy, we can determine the wavelength of the second re-emitted photon.
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A proton of 300 nm is absorbed by a gas and then re- mitted photons has wave length 496 nm ,the wave length of second re emitted photon is ?
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