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100gm of CaCO3 is treated with 500ml of M/2 solution of HCl. find out the volume of CO2 evolved at STP.?
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100gm of CaCO3 is treated with 500ml of M/2 solution of HCl. find out ...
100g caco3=1 mole 500ml m/2 hcl= 1/4 mole as the stochiometric equation 1mol caco3=2 mol hcl=1 mol CO2 hence hcl is the limiting reagent since 2 mol hcl produce 1mol CO2 1/4 mol would produce =1/8 mol CO2=22.4/8=2.8 litre
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100gm of CaCO3 is treated with 500ml of M/2 solution of HCl. find out ...
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100gm of CaCO3 is treated with 500ml of M/2 solution of HCl. find out the volume of CO2 evolved at STP.?
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