From the top Of a building , 39.2m tall , a boy projects a stone verti...
Problem:
A boy projects a stone vertically upward from the top of a building, 39.2m tall, with an initial velocity of 9.8 m/s. When will the stone pass through the point of projection?
Solution:
Step 1: Analyze the problem
To solve this problem, we need to use the kinematic equations of motion. We know that the stone is projected vertically upward, so the acceleration due to gravity will act in the opposite direction to the initial velocity. We also know that the final displacement of the stone will be zero when it passes through the point of projection.
Step 2: Determine the variables
We can use the following variables to solve the problem:
- u = initial velocity = 9.8 m/s
- v = final velocity = 0 m/s
- a = acceleration due to gravity = -9.8 m/s^2
- s = displacement = -39.2 m (negative because the stone is moving downward)
- t = time
Step 3: Apply the kinematic equations
We can use the following kinematic equation to solve for time:
s = ut + (1/2)at^2
Plugging in the values, we get:
-39.2 = 9.8t + (1/2)(-9.8)t^2
Simplifying and solving for t, we get:
t = 4 seconds
Step 4: Interpret the result
Therefore, the stone will pass through the point of projection after 4 seconds.