Calculation of Remaining CO2

Given:
- Initial amount of CO2 = 22 mg
- Number of removed molecules = 10^21

To calculate the remaining CO2, we need to convert the initial amount from milligrams (mg) to grams (g).

1 mg = 0.001 g

So, the initial amount of CO2 in grams is:
22 mg * 0.001 g/mg = 0.022 g

Calculating the Moles of CO2

To calculate the moles of CO2, we need to know the molar mass of CO2. The molar mass of CO2 is the sum of the atomic masses of carbon (C) and two oxygen (O) atoms.

The atomic mass of carbon (C) = 12.01 g/mol
The atomic mass of oxygen (O) = 16.00 g/mol

Molar mass of CO2 = (12.01 g/mol) + 2 * (16.00 g/mol) = 44.01 g/mol

Now, we can calculate the moles of CO2 using the formula:

moles = mass / molar mass

moles of CO2 = 0.022 g / 44.01 g/mol = 0.000499 moles (approximately)

Calculating the Remaining CO2 and Moles of CO2

Since 10^21 molecules of CO2 are removed, we need to subtract the corresponding number of molecules from the initial number of molecules.

The Avogadro's number (6.022 x 10^23) represents the number of molecules in one mole of a substance.

Number of molecules in 1 mole of CO2 = 6.022 x 10^23

Number of molecules in 0.000499 moles of CO2 = (0.000499 moles / 1 mole) * (6.022 x 10^23 molecules / 1 mole) = 3.011 x 10^20 molecules

Remaining molecules of CO2 = Initial molecules - Removed molecules = (6.022 x 10^23 molecules) - (10^21 molecules) = 5.022 x 10^23 molecules

To convert the remaining molecules to grams and moles, we can use the molar mass of CO2.

Remaining grams of CO2 = (Remaining molecules / 6.022 x 10^23 molecules) * (44.01 g/mol) = (5.022 x 10^23 molecules / 6.022 x 10^23 molecules) * (44.01 g/mol) = 36.75 g

Remaining moles of CO2 = Remaining grams / Molar mass = 36.75 g / 44.01 g/mol = 0.835 moles (approximately)

Summary

After removing 10^21 molecules of CO2 from an initial amount of 22 mg, the remaining amount of CO2 is approximately 36.75 grams and the remaining moles of CO2 is approximately 0.835 moles.

2.88*10^-3mole of CO2 is left