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While cooling, a cubical casting of side 40 mm undergoes 3%, 4% and 5% volume shrinkage during the liquid state, phase transition and solid state, respectively. The volume of metal compensated from the riser is  
  • a)
    2%  
  • b)
    7%  
  • c)
    8%  
  • d)
    9% 
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
While cooling, a cubical casting of side 40 mm undergoes 3%, 4% and 5%...
The riser can compensate for volume shrinkage only in the liquid stage and transition stage and not in the solid state.
Hence volume of metal that needs to be compensated from the riser =3+4=7%
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Most Upvoted Answer
While cooling, a cubical casting of side 40 mm undergoes 3%, 4% and 5%...
To find the volume of metal compensated from the riser, we need to calculate the overall volume shrinkage of the casting during the cooling process.

Given:
Side of the cubical casting = 40 mm
Volume shrinkage during the liquid state = 3%
Volume shrinkage during the phase transition = 4%
Volume shrinkage during the solid state = 5%

Let's calculate the volume of the casting before shrinkage:
Volume of the cubical casting = (Side)^3 = (40 mm)^3 = 64000 mm^3

Now, let's calculate the volume shrinkage during each stage and the final volume of the casting after shrinkage:

1. Volume shrinkage during the liquid state:
Volume shrinkage = 3% of the initial volume
= 3/100 * 64000 mm^3
= 1920 mm^3

Volume after liquid state shrinkage = Initial volume - Shrinkage during liquid state
= 64000 mm^3 - 1920 mm^3
= 62080 mm^3

2. Volume shrinkage during the phase transition:
Volume shrinkage = 4% of the volume after liquid state shrinkage
= 4/100 * 62080 mm^3
= 2483.2 mm^3

Volume after phase transition shrinkage = Volume after liquid state shrinkage - Shrinkage during phase transition
= 62080 mm^3 - 2483.2 mm^3
= 59596.8 mm^3

3. Volume shrinkage during the solid state:
Volume shrinkage = 5% of the volume after phase transition shrinkage
= 5/100 * 59596.8 mm^3
= 2979.84 mm^3

Volume after solid state shrinkage = Volume after phase transition shrinkage - Shrinkage during solid state
= 59596.8 mm^3 - 2979.84 mm^3
= 56616.96 mm^3

Finally, let's calculate the volume of metal compensated from the riser:
Volume of metal compensated = Initial volume - Volume after solid state shrinkage
= 64000 mm^3 - 56616.96 mm^3
= 7399.04 mm^3

Now, let's calculate the percentage of metal compensated from the riser:
Percentage of metal compensated = (Volume of metal compensated / Initial volume) * 100
= (7399.04 mm^3 / 64000 mm^3) * 100
≈ 11.56%

Therefore, the correct answer is not given in the options.
Free Test
Community Answer
While cooling, a cubical casting of side 40 mm undergoes 3%, 4% and 5%...
In cooling process in casting there will be two liquid phase transition and one solid phase transition
liquid shrinkage is compensated by riser and solid shrinkage by shrinkage allowance
so I. question the volume of metal compensated by riser is 3%+4%=7%
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While cooling, a cubical casting of side 40 mm undergoes 3%, 4% and 5% volume shrinkage during the liquid state, phase transition and solid state, respectively. The volume of metal compensated from the riser isa)2% b)7% c)8% d)9%Correct answer is option 'B'. Can you explain this answer?
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