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General equation of a straight line is:a)y = mx + cb)Ax + By + C = 0c)Ax2 + By2 + C = 0d)-A/B + By + C/B = 0Correct answer is option 'B'. Can you explain this answer? for JEE 2026 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about General equation of a straight line is:a)y = mx + cb)Ax + By + C = 0c)Ax2 + By2 + C = 0d)-A/B + By + C/B = 0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for General equation of a straight line is:a)y = mx + cb)Ax + By + C = 0c)Ax2 + By2 + C = 0d)-A/B + By + C/B = 0Correct answer is option 'B'. Can you explain this answer?.

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