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Four containers of 2 litre capacity contains dinitrogen as described below. which one contains maximum number of molecules under similar conditions. (a) 2.5 gram molecules of dinitrogen (b) 4 gram atom of Nitrogen (c) 3.01×10^24N atoms (d) 84 gram of dinitrogen?
correct answer is option (d)explain the answer?
correct answer is option (d)explain the answer?
Most Upvoted Answer
Four containers of 2 litre capacity contains dinitrogen as described b...
Maximum number of molecules of dinitrogen in a container of 2 litre will be present if the container has the highest mass of dinitrogen. This is because the number of molecules of dinitrogen is directly proportional to its mass.
(a) 2.5 gram molecules of dinitrogen: This is an incorrect unit as molecules do not have a mass. The correct unit should be grams of dinitrogen.
(b) 4 gram atom of Nitrogen: 1 mole of nitrogen contains Avogadro's number (6.02 x 10^23) atoms. Therefore, 4 gram atoms of nitrogen will contain (4/14) moles of nitrogen atoms. This is equivalent to (4/14) x 6.02 x 10^23 = 1.72 x 10^23 nitrogen atoms. Since each molecule of dinitrogen contains 2 nitrogen atoms, the number of molecules of dinitrogen will be 1.72 x 10^23 / 2 = 8.6 x 10^22 molecules.
(c) 3.01×10^24N atoms: This is equivalent to (3.01 x 10^24) / (6.02 x 10^23) = 5 moles of nitrogen atoms. Since each molecule of dinitrogen contains 2 nitrogen atoms, the number of molecules of dinitrogen will be 5 x (6.02 x 10^23) / 2 = 1.51 x 10^24 molecules.
(d) 84 gram of dinitrogen: The molar mass of dinitrogen is 28 g/mol. Therefore, 84 g of dinitrogen is equivalent to 3 moles of dinitrogen. Since each mole of dinitrogen contains Avogadro's number (6.02 x 10^23) molecules, the total number of molecules of dinitrogen will be 3 x (6.02 x 10^23) = 1.81 x 10^24 molecules.
Therefore, option (d) 84 gram of dinitrogen contains the maximum number of molecules of dinitrogen in a container of 2 litre.
(a) 2.5 gram molecules of dinitrogen: This is an incorrect unit as molecules do not have a mass. The correct unit should be grams of dinitrogen.
(b) 4 gram atom of Nitrogen: 1 mole of nitrogen contains Avogadro's number (6.02 x 10^23) atoms. Therefore, 4 gram atoms of nitrogen will contain (4/14) moles of nitrogen atoms. This is equivalent to (4/14) x 6.02 x 10^23 = 1.72 x 10^23 nitrogen atoms. Since each molecule of dinitrogen contains 2 nitrogen atoms, the number of molecules of dinitrogen will be 1.72 x 10^23 / 2 = 8.6 x 10^22 molecules.
(c) 3.01×10^24N atoms: This is equivalent to (3.01 x 10^24) / (6.02 x 10^23) = 5 moles of nitrogen atoms. Since each molecule of dinitrogen contains 2 nitrogen atoms, the number of molecules of dinitrogen will be 5 x (6.02 x 10^23) / 2 = 1.51 x 10^24 molecules.
(d) 84 gram of dinitrogen: The molar mass of dinitrogen is 28 g/mol. Therefore, 84 g of dinitrogen is equivalent to 3 moles of dinitrogen. Since each mole of dinitrogen contains Avogadro's number (6.02 x 10^23) molecules, the total number of molecules of dinitrogen will be 3 x (6.02 x 10^23) = 1.81 x 10^24 molecules.
Therefore, option (d) 84 gram of dinitrogen contains the maximum number of molecules of dinitrogen in a container of 2 litre.
Community Answer
Four containers of 2 litre capacity contains dinitrogen as described b...
Yes d is answer..Bcz 84÷14 =6 so 6 moles of dinitrigen is present..So..6×6.023×10^23 molecules are present
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Four containers of 2 litre capacity contains dinitrogen as described below. which one contains maximum number of molecules under similar conditions. (a) 2.5 gram molecules of dinitrogen (b) 4 gram atom of Nitrogen (c) 3.01×10^24N atoms (d) 84 gram of dinitrogen?correct answer is option (d)explain the answer?
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Four containers of 2 litre capacity contains dinitrogen as described below. which one contains maximum number of molecules under similar conditions. (a) 2.5 gram molecules of dinitrogen (b) 4 gram atom of Nitrogen (c) 3.01×10^24N atoms (d) 84 gram of dinitrogen?correct answer is option (d)explain the answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Four containers of 2 litre capacity contains dinitrogen as described below. which one contains maximum number of molecules under similar conditions. (a) 2.5 gram molecules of dinitrogen (b) 4 gram atom of Nitrogen (c) 3.01×10^24N atoms (d) 84 gram of dinitrogen?correct answer is option (d)explain the answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Four containers of 2 litre capacity contains dinitrogen as described below. which one contains maximum number of molecules under similar conditions. (a) 2.5 gram molecules of dinitrogen (b) 4 gram atom of Nitrogen (c) 3.01×10^24N atoms (d) 84 gram of dinitrogen?correct answer is option (d)explain the answer?.
Four containers of 2 litre capacity contains dinitrogen as described below. which one contains maximum number of molecules under similar conditions. (a) 2.5 gram molecules of dinitrogen (b) 4 gram atom of Nitrogen (c) 3.01×10^24N atoms (d) 84 gram of dinitrogen?correct answer is option (d)explain the answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Four containers of 2 litre capacity contains dinitrogen as described below. which one contains maximum number of molecules under similar conditions. (a) 2.5 gram molecules of dinitrogen (b) 4 gram atom of Nitrogen (c) 3.01×10^24N atoms (d) 84 gram of dinitrogen?correct answer is option (d)explain the answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Four containers of 2 litre capacity contains dinitrogen as described below. which one contains maximum number of molecules under similar conditions. (a) 2.5 gram molecules of dinitrogen (b) 4 gram atom of Nitrogen (c) 3.01×10^24N atoms (d) 84 gram of dinitrogen?correct answer is option (d)explain the answer?.
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