Question Description
Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared
according to
the JEE exam syllabus. Information about Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y? covers all topics & solutions for JEE 2025 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y?.
Solutions for Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y? defined & explained in the simplest way possible. Besides giving the explanation of
Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y?, a detailed solution for Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y? has been provided alongside types of Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y? theory, EduRev gives you an
ample number of questions to practice Find the square root of (-8-6i) let x+iy=√(-8-6i) squaring on both sides x2-2+2xyi=-8-6i equating I term,real term x2-y2=-8---equ1 2xy=-6equ2 w.K.T x2+y2=√[[x2-y2)2+(2xy)2] equ3 sub's 1,2in3 we get x2+y2=10 form this we can find x,y hence √[-8-6i)is x+iy=+or-(1+3i) I know only this method plz tell another method frnd s x2 is square of x same in y? tests, examples and also practice JEE tests.