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Only two isomers of monochloro product is possible of
- a)n-butane
- b)2,4-dimethyl pentane
- c)benzene
- d)1-methyl propane
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Only two isomers of monochloro product is possible ofa)n-butaneb)2,4-d...
In case of n-butane (CH3−CH2−CH2−CH3) are two isomers will be obtained depending on whether cl atom adds on to carbon-2 or carbon -1
In (ii)
We will get two isomers with Cl atom at either one of the −CH3 groups or on the central c-atom.
Hence b is the correct answer.
Most Upvoted Answer
Only two isomers of monochloro product is possible ofa)n-butaneb)2,4-d...
Yes, there are only two isomers for mono-chloro derivatives of n-butane, because even though you think you got more than 2, you must have gone wrong somewhere, because you will get the mirror image of the isomers, which are the same.
Thus the only 2 mono-chloro derivatives of n-butane are
1) 1-chloro butane
2) 2-chloro butane
Thus the only 2 mono-chloro derivatives of n-butane are
1) 1-chloro butane
2) 2-chloro butane
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Community Answer
Only two isomers of monochloro product is possible ofa)n-butaneb)2,4-d...
Monochloro Isomers:
Monochloro isomers refer to compounds that have a single chlorine atom attached to different carbon atoms within the molecule. In other words, they are structural isomers that differ in the position of the chlorine atom in the compound.
Explanation of Answer:
The correct answer is option 'A' - n-butane. Let's understand why only two isomers of the monochloro product are possible for each given compound.
1. n-Butane:
n-Butane is a straight-chain alkane with four carbon atoms. The possible isomers of the monochloro product can be determined by considering the different positions where the chlorine atom can be attached.
- The chlorine atom can be attached to the first carbon atom, resulting in 1-chlorobutane.
- The chlorine atom can also be attached to the second carbon atom, resulting in 2-chlorobutane.
Since n-butane is a linear molecule with no branches, there are no other carbon atoms available for the chlorine atom to attach. Therefore, only these two isomers are possible for n-butane.
2. 2,4-Dimethyl Pentane:
2,4-Dimethyl pentane is an alkane with five carbon atoms, two methyl groups (CH3) attached to the second and fourth carbon atoms, and no branches on the remaining carbon atoms.
- The chlorine atom can be attached to the third carbon atom, resulting in 3-chloro-2,4-dimethyl pentane.
- The chlorine atom can also be attached to the fifth carbon atom, resulting in 5-chloro-2,4-dimethyl pentane.
Since the methyl groups are attached to specific carbon atoms, the chlorine atom can only attach to the third or fifth carbon atom. Therefore, only these two isomers are possible for 2,4-dimethyl pentane.
3. Benzene:
Benzene is an aromatic compound with a ring structure. It does not have any available carbon atoms for the chlorine atom to attach. Therefore, no isomers of the monochloro product are possible for benzene.
4. 1-Methyl Propane:
1-Methyl propane is an alkane with three carbon atoms, where one methyl group (CH3) is attached to the first carbon atom.
- The chlorine atom can be attached to the second carbon atom, resulting in 2-chloro-1-methyl propane.
Since there are no other carbon atoms available for the chlorine atom to attach, only this isomer is possible for 1-methyl propane.
Therefore, out of the given compounds, only n-butane has two possible isomers of the monochloro product.
Monochloro isomers refer to compounds that have a single chlorine atom attached to different carbon atoms within the molecule. In other words, they are structural isomers that differ in the position of the chlorine atom in the compound.
Explanation of Answer:
The correct answer is option 'A' - n-butane. Let's understand why only two isomers of the monochloro product are possible for each given compound.
1. n-Butane:
n-Butane is a straight-chain alkane with four carbon atoms. The possible isomers of the monochloro product can be determined by considering the different positions where the chlorine atom can be attached.
- The chlorine atom can be attached to the first carbon atom, resulting in 1-chlorobutane.
- The chlorine atom can also be attached to the second carbon atom, resulting in 2-chlorobutane.
Since n-butane is a linear molecule with no branches, there are no other carbon atoms available for the chlorine atom to attach. Therefore, only these two isomers are possible for n-butane.
2. 2,4-Dimethyl Pentane:
2,4-Dimethyl pentane is an alkane with five carbon atoms, two methyl groups (CH3) attached to the second and fourth carbon atoms, and no branches on the remaining carbon atoms.
- The chlorine atom can be attached to the third carbon atom, resulting in 3-chloro-2,4-dimethyl pentane.
- The chlorine atom can also be attached to the fifth carbon atom, resulting in 5-chloro-2,4-dimethyl pentane.
Since the methyl groups are attached to specific carbon atoms, the chlorine atom can only attach to the third or fifth carbon atom. Therefore, only these two isomers are possible for 2,4-dimethyl pentane.
3. Benzene:
Benzene is an aromatic compound with a ring structure. It does not have any available carbon atoms for the chlorine atom to attach. Therefore, no isomers of the monochloro product are possible for benzene.
4. 1-Methyl Propane:
1-Methyl propane is an alkane with three carbon atoms, where one methyl group (CH3) is attached to the first carbon atom.
- The chlorine atom can be attached to the second carbon atom, resulting in 2-chloro-1-methyl propane.
Since there are no other carbon atoms available for the chlorine atom to attach, only this isomer is possible for 1-methyl propane.
Therefore, out of the given compounds, only n-butane has two possible isomers of the monochloro product.
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Only two isomers of monochloro product is possible ofa)n-butaneb)2,4-dimethyl pentanec)benzened)1-methyl propaneCorrect answer is option 'A'. Can you explain this answer?
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