A partially dried clay mineral contains 8% water. The original sample ...
Given:
- Original sample contains 12% water and 45% silica
- Partially dried sample contains 8% water
To find:
- Percentage of silica in the partially dried sample
Solution:
Let's assume the original sample weighs 100 grams.
- The original sample contains 12 grams of water and 45 grams of silica.
- The remaining weight is made up of other components, such as clay minerals, which we can assume to be x grams.
Calculating the weight of the partially dried sample:
- The partially dried sample contains 8 grams of water.
- The weight of the partially dried sample can be calculated as follows:
Weight of partially dried sample = Weight of original sample - Weight of water lost during drying
Weight of partially dried sample = 100 grams - 12 grams + 8 grams = 96 grams
Calculating the weight of silica in the partially dried sample:
- The weight of silica in the partially dried sample can be calculated using the proportion of silica in the original sample.
- The weight of silica in the partially dried sample can be represented as (45 grams / 100 grams) * 96 grams = 43.2 grams.
Calculating the percentage of silica in the partially dried sample:
- The percentage of silica in the partially dried sample can be calculated using the formula:
Percentage of silica = (Weight of silica / Weight of partially dried sample) * 100
Percentage of silica = (43.2 grams / 96 grams) * 100 = 45%
Conclusion:
The percentage of silica in the partially dried sample is 45%. Therefore, the correct answer is option D) 47%.