Angular Momentum of Electron in "d" Orbital
The angular momentum of an electron in a "d" orbital can be calculated using the formula L = √(l(l+1)) ħ, where ħ is the reduced Planck constant and l is the azimuthal quantum number corresponding to the "d" orbital (l=2).

Calculation:
- Substituting l=2 into the formula, we get L = √(2(2+1)) ħ
- L = √(6) ħ
- L = √6 ħ
Therefore, the angular momentum of an electron in a "d" orbital is equal to √6 ħ.

Explanation:
- The angular momentum of an electron is a vector quantity that describes the rotation of the electron around the nucleus.
- In the case of a "d" orbital, the electron moves in a more complex 3-dimensional shape compared to the simpler s and p orbitals.
- The azimuthal quantum number (l) determines the shape of the orbital and influences the angular momentum of the electron.
- The square root of the product of l and (l+1) gives us the magnitude of the angular momentum.
In conclusion, the angular momentum of an electron in a "d" orbital is given by the square root of 6 times the reduced Planck constant.