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Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -
- a)10%
- b)20%
- c)30%
- d)40%
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic ...
π = iCRT
K3[Fe(CN)6] = 3k+ + [Fe(CN)6]3–
i = (1 + 3α)
α = 0.2
so 20%
K3[Fe(CN)6] = 3k+ + [Fe(CN)6]3–
i = (1 + 3α)
α = 0.2
so 20%
Most Upvoted Answer
Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic ...
Osmotic pressure of a solution is given by the formula: π = MRTi where M is the molar concentration of the solute, R is the gas constant, T is the temperature in Kelvin and i is the van't Hoff factor.
Given, osmotic pressure (π) = 3.94 atm
Molar concentration (M) = 0.1 M
Temperature (T) = 27 + 273 = 300 K
Van't Hoff factor (i) = ?
We know that potassium ferricyanide dissociates into K+ and [Fe(CN)6]3- ions in water. Each formula unit of K3[Fe(CN)6] produces 4 ions, which means i = 4.
Substituting the values in the formula, we get: 3.94 = (0.1 x 0.0821 x 300 x 4) x i
Solving for i, we get: i = 1.22
The percent ionisation of the solute is given by: % ionisation = (i - 1) / i x 100
Substituting the value of i, we get: % ionisation = (1.22 - 1) / 1.22 x 100 = 18.85 ~ 20% (approx)
Therefore, the correct answer is option B, 20%.
Given, osmotic pressure (π) = 3.94 atm
Molar concentration (M) = 0.1 M
Temperature (T) = 27 + 273 = 300 K
Van't Hoff factor (i) = ?
We know that potassium ferricyanide dissociates into K+ and [Fe(CN)6]3- ions in water. Each formula unit of K3[Fe(CN)6] produces 4 ions, which means i = 4.
Substituting the values in the formula, we get: 3.94 = (0.1 x 0.0821 x 300 x 4) x i
Solving for i, we get: i = 1.22
The percent ionisation of the solute is given by: % ionisation = (i - 1) / i x 100
Substituting the value of i, we get: % ionisation = (1.22 - 1) / 1.22 x 100 = 18.85 ~ 20% (approx)
Therefore, the correct answer is option B, 20%.
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Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -a)10%b)20%c)30%d)40%Correct answer is option 'B'. Can you explain this answer?
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