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Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -
- a)10%
- b)20%
- c)30%
- d)40%
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic ...
π = iCRT
K3[Fe(CN)6] = 3k+ + [Fe(CN)6]3–
i = (1 + 3α)
α = 0.2
so 20%
K3[Fe(CN)6] = 3k+ + [Fe(CN)6]3–
i = (1 + 3α)
α = 0.2
so 20%
Most Upvoted Answer
Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic ...
Osmotic pressure of a solution is given by the formula: π = MRTi where M is the molar concentration of the solute, R is the gas constant, T is the temperature in Kelvin and i is the van't Hoff factor.
Given, osmotic pressure (π) = 3.94 atm
Molar concentration (M) = 0.1 M
Temperature (T) = 27 + 273 = 300 K
Van't Hoff factor (i) = ?
We know that potassium ferricyanide dissociates into K+ and [Fe(CN)6]3- ions in water. Each formula unit of K3[Fe(CN)6] produces 4 ions, which means i = 4.
Substituting the values in the formula, we get: 3.94 = (0.1 x 0.0821 x 300 x 4) x i
Solving for i, we get: i = 1.22
The percent ionisation of the solute is given by: % ionisation = (i - 1) / i x 100
Substituting the value of i, we get: % ionisation = (1.22 - 1) / 1.22 x 100 = 18.85 ~ 20% (approx)
Therefore, the correct answer is option B, 20%.
Given, osmotic pressure (π) = 3.94 atm
Molar concentration (M) = 0.1 M
Temperature (T) = 27 + 273 = 300 K
Van't Hoff factor (i) = ?
We know that potassium ferricyanide dissociates into K+ and [Fe(CN)6]3- ions in water. Each formula unit of K3[Fe(CN)6] produces 4 ions, which means i = 4.
Substituting the values in the formula, we get: 3.94 = (0.1 x 0.0821 x 300 x 4) x i
Solving for i, we get: i = 1.22
The percent ionisation of the solute is given by: % ionisation = (i - 1) / i x 100
Substituting the value of i, we get: % ionisation = (1.22 - 1) / 1.22 x 100 = 18.85 ~ 20% (approx)
Therefore, the correct answer is option B, 20%.
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Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -a)10%b)20%c)30%d)40%Correct answer is option 'B'. Can you explain this answer?
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Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -a)10%b)20%c)30%d)40%Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -a)10%b)20%c)30%d)40%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -a)10%b)20%c)30%d)40%Correct answer is option 'B'. Can you explain this answer?.
Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -a)10%b)20%c)30%d)40%Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -a)10%b)20%c)30%d)40%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Decimolar solution of potassium ferricyanide, K3[Fe(CN)6] has osmotic pressure of 3.94 atm at 27ºC. Hence percent ionisation of the solute is -a)10%b)20%c)30%d)40%Correct answer is option 'B'. Can you explain this answer?.
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