A ball is dropped from height.if it takes 0.2 seconds to cross the las...
For last 6m distance travelled , s=6m
time=0.2s
initial velocity=?
a=g=9.8m/s2
s=ut+1/2at^2
=6=u(0.2)+1/2 x 9.8 x0.2x0.2
6=0.2 u + 4.9 x 0.04
u=5.8/0.2
u=29m/s
For distance x, u=0m/s
v=29m/s [ because initial velocity will be final]
a=g=9.8m/s2
s= v^2-u^2/2a
=29^2-0^2/2x9.8
=29x29/19.6
s=42.5m
Total distance=42.5 +6=48.5 m
This question is part of UPSC exam. View all JEE courses
A ball is dropped from height.if it takes 0.2 seconds to cross the las...
Given:
- The ball takes 0.2 seconds to cross the last 6 m before hitting the ground.
- Acceleration due to gravity (g) is 10 m/s^2.
To find:
The height from which the ball was dropped.
Solution:
Step 1: Understanding the problem
- The ball is dropped from a certain height and falls freely under the influence of gravity.
- The time taken to cross the last 6 m before hitting the ground is given as 0.2 seconds.
Step 2: Analyzing the motion of the ball
- The motion of the ball is governed by the equations of motion.
- The equation for the distance fallen by an object in free fall is given by:
- h = ut + (1/2)gt^2
- where h is the height, u is the initial velocity (which is 0 as the ball is dropped), g is the acceleration due to gravity, and t is the time taken.
Step 3: Applying the equation of motion
- In this case, the height h is the distance the ball fell before hitting the ground.
- The time taken t is given as 0.2 seconds.
- The acceleration due to gravity g is given as 10 m/s^2.
- Substituting the given values into the equation of motion, we have:
- h = 0 + (1/2)(10)(0.2)^2
- h = 0.01 m
Step 4: Converting the distance to height
- The distance fallen by the ball is given as 0.01 m.
- To find the height from which the ball was dropped, we subtract this distance from the total height.
- Since the total height is not given, we need to find it.
Step 5: Finding the total height
- The ball takes 0.2 seconds to cross the last 6 m before hitting the ground.
- Using the equation of motion, we have:
- 6 = 0 + (1/2)(10)(0.2)^2
- 6 = 0.02 m
Step 6: Calculating the height from which the ball is dropped
- The total height is given as 0.02 m.
- To find the height from which the ball was dropped, we subtract the distance fallen (0.01 m) from the total height:
- Height = Total height - Distance fallen
- Height = 0.02 - 0.01
- Height = 0.01 m
Step 7: Converting the height to meters
- The height is given in meters.
- Converting the height from meters to centimeters, we have:
- Height = 0.01 m * 100 cm/m
- Height = 1 cm
Step 8: Converting the height to kilometers
- The height is given in centimeters.
- Converting the height from centimeters to kilometers, we have:
- Height = 1 cm * (1 km/100000 cm)
- Height = 0.00001 km
Step 9:
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.