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A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when the cell is shu ted by a resistance of 4 ohm the balancing length is reduced by 30 cm what is the internal resistance of the cell?
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A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when t...
Calculation of Internal Resistance of a Cell
Given Information:
- EMF of the cell = 12V
- Length of potentiometer wire for balancing the cell = 150cm
- Resistance of shunt = 4ohm
- Length of potentiometer wire after reducing balancing length = 120cm
Solution:
Let the internal resistance of the cell be 'r'.
For balancing the cell, we have:
V = I(R+r) ... (1)
Where, V is the EMF of the cell, I is the current through the circuit, R is the resistance of the potentiometer wire, and r is the internal resistance of the cell.
At the balancing length, the potential difference across the shunt is equal to the potential difference across the potentiometer wire.
Therefore, we have:
Ir = V - I(R+x) ... (2)
Where, x is the balancing length.
From equations (1) and (2), we get:
Ir = V - IR - Ir
Or, I(R+r) = V - I(R+x)
Or, IR + Ir = V - Ix
Or, I = V / (R+r)
Substituting the value of I in equation (2), we get:
r = (x / (150 - x)) * R
Substituting the given values, we get:
r = (30 / 120) * 4 = 1 ohm
Answer:
Therefore, the internal resistance of the cell is 1 ohm.
Community Answer
A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when t...
L1=150
L2=120
r=R[(L1/L2)-1]
Hennce, r=4×(30/150)
r=0.8ohms
L2=120
r=R[(L1/L2)-1]
Hennce, r=4×(30/150)
r=0.8ohms
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A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when the cell is shu ted by a resistance of 4 ohm the balancing length is reduced by 30 cm what is the internal resistance of the cell?
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A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when the cell is shu ted by a resistance of 4 ohm the balancing length is reduced by 30 cm what is the internal resistance of the cell? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when the cell is shu ted by a resistance of 4 ohm the balancing length is reduced by 30 cm what is the internal resistance of the cell? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when the cell is shu ted by a resistance of 4 ohm the balancing length is reduced by 30 cm what is the internal resistance of the cell?.
A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when the cell is shu ted by a resistance of 4 ohm the balancing length is reduced by 30 cm what is the internal resistance of the cell? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when the cell is shu ted by a resistance of 4 ohm the balancing length is reduced by 30 cm what is the internal resistance of the cell? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cell of e.m.f 12v is balanced by 150 cm of potentiometer wire when the cell is shu ted by a resistance of 4 ohm the balancing length is reduced by 30 cm what is the internal resistance of the cell?.
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