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The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+ → X2+ + Y will be spontaneous when: [AIEEE 2012]
- a)X = Fe, Y = Zn
- b)X = Zn, Y = Ni
- c)X = Ni, Y = Fe
- d)X = Ni, Y = Zn
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe ar...
X = Zn, Y = Ni
Zn + Ni2+ →Zn2+ + Ni
Zn + Ni2+ →Zn2+ + Ni
Most Upvoted Answer
The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe ar...
Zn+² to zn = - 0.76
so zn to zn+² = +0.76(spontaneous)
Ni+² to Ni = - 0.23
adding both we get
Zn + Ni+² gives Zn+² + Ni.
0.76 - 0.23= +0.53
since final answer is + in only this case.
+ potential will be spontaneous reaction
so zn to zn+² = +0.76(spontaneous)
Ni+² to Ni = - 0.23
adding both we get
Zn + Ni+² gives Zn+² + Ni.
0.76 - 0.23= +0.53
since final answer is + in only this case.
+ potential will be spontaneous reaction
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Community Answer
The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe ar...
The reaction is:
X + Y2 -> X2 + Y
To determine the standard reduction potential for this reaction, we can use the Nernst equation:
Ecell = E°cell - (0.0592/n) * log(Q)
where Ecell is the cell potential, E°cell is the standard cell potential, n is the number of electrons transferred in the reaction, and Q is the reaction quotient.
In this case, n = 2 because 2 electrons are transferred in the reaction.
To determine the reaction quotient, we can use the concentrations of the species involved in the reaction. However, the concentrations are not provided in the question, so we cannot calculate the reaction quotient.
Therefore, we cannot determine the standard reduction potential for the reaction X + Y2 -> X2 + Y with the given information.
X + Y2 -> X2 + Y
To determine the standard reduction potential for this reaction, we can use the Nernst equation:
Ecell = E°cell - (0.0592/n) * log(Q)
where Ecell is the cell potential, E°cell is the standard cell potential, n is the number of electrons transferred in the reaction, and Q is the reaction quotient.
In this case, n = 2 because 2 electrons are transferred in the reaction.
To determine the reaction quotient, we can use the concentrations of the species involved in the reaction. However, the concentrations are not provided in the question, so we cannot calculate the reaction quotient.
Therefore, we cannot determine the standard reduction potential for the reaction X + Y2 -> X2 + Y with the given information.
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The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+→X2++ Y will be spontaneous when: [AIEEE 2012]a)X = Fe, Y = Znb)X = Zn, Y = Nic)X = Ni, Y = Fed)X = Ni, Y = ZnCorrect answer is option 'B'. Can you explain this answer?
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The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+→X2++ Y will be spontaneous when: [AIEEE 2012]a)X = Fe, Y = Znb)X = Zn, Y = Nic)X = Ni, Y = Fed)X = Ni, Y = ZnCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+→X2++ Y will be spontaneous when: [AIEEE 2012]a)X = Fe, Y = Znb)X = Zn, Y = Nic)X = Ni, Y = Fed)X = Ni, Y = ZnCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+→X2++ Y will be spontaneous when: [AIEEE 2012]a)X = Fe, Y = Znb)X = Zn, Y = Nic)X = Ni, Y = Fed)X = Ni, Y = ZnCorrect answer is option 'B'. Can you explain this answer?.
The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+→X2++ Y will be spontaneous when: [AIEEE 2012]a)X = Fe, Y = Znb)X = Zn, Y = Nic)X = Ni, Y = Fed)X = Ni, Y = ZnCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+→X2++ Y will be spontaneous when: [AIEEE 2012]a)X = Fe, Y = Znb)X = Zn, Y = Nic)X = Ni, Y = Fed)X = Ni, Y = ZnCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+→X2++ Y will be spontaneous when: [AIEEE 2012]a)X = Fe, Y = Znb)X = Zn, Y = Nic)X = Ni, Y = Fed)X = Ni, Y = ZnCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The standard reduction potentials for Zn2+/Zn, Ni2+/Ni, and Fe2+/Fe are -0.76, -0.23 and -0.44 V respectively. The reaction X + Y2+→X2++ Y will be spontaneous when: [AIEEE 2012]a)X = Fe, Y = Znb)X = Zn, Y = Nic)X = Ni, Y = Fed)X = Ni, Y = ZnCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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