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A bar magnet of magnetic moment 1.5 J/T lies aligned with the direction of a uniform magnetic field of 0.22 T. What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction?
- a)0.66J
- b)0.76J nC
- c)0.86J
- d)0.56J
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A bar magnet of magnetic moment 1.5 J/T lies aligned with the directio...
Magnetic moment, M= 1.5 J T-1
Magnetic field strength, B= 0.22 T
W = - MB (cos θ2 - cos θ1)
= -1.5 x 0.22 (cos 180° - cos 0°)
= -0.33 (-1 - 1)
= 0.66 J
= -1.5 x 0.22 (cos 180° - cos 0°)
= -0.33 (-1 - 1)
= 0.66 J
Most Upvoted Answer
A bar magnet of magnetic moment 1.5 J/T lies aligned with the directio...
Given data:
- Magnetic moment of the bar magnet, m = 1.5 J/T
- Magnetic field, B = 0.22 T
Formula used:
- The work done in turning the magnet is given by the formula:
\[ W = -\vec{M} \cdot \vec{B} \]
Calculation:
- Given that the magnetic moment of the bar magnet is aligned with the field direction, the angle between the magnetic moment and the field direction is 0 degrees.
- When the magnet is turned to align its magnetic moment opposite to the field direction, the angle between the magnetic moment and the field direction is 180 degrees.
Substitute the values into the formula:
\[ W = -mB\cos\theta \]
\[ W = -1.5 \times 0.22 \times \cos(180) \]
\[ W = -0.33 \times (-1) \]
\[ W = 0.33 J \]
Therefore, the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction is 0.33 J.
Correct Answer:
- Option (a) 0.66J
- Magnetic moment of the bar magnet, m = 1.5 J/T
- Magnetic field, B = 0.22 T
Formula used:
- The work done in turning the magnet is given by the formula:
\[ W = -\vec{M} \cdot \vec{B} \]
Calculation:
- Given that the magnetic moment of the bar magnet is aligned with the field direction, the angle between the magnetic moment and the field direction is 0 degrees.
- When the magnet is turned to align its magnetic moment opposite to the field direction, the angle between the magnetic moment and the field direction is 180 degrees.
Substitute the values into the formula:
\[ W = -mB\cos\theta \]
\[ W = -1.5 \times 0.22 \times \cos(180) \]
\[ W = -0.33 \times (-1) \]
\[ W = 0.33 J \]
Therefore, the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction is 0.33 J.
Correct Answer:
- Option (a) 0.66J
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A bar magnet of magnetic moment 1.5 J/T lies aligned with the direction of a uniform magnetic field of 0.22 T. What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction?a)0.66Jb)0.76J nCc)0.86Jd)0.56JCorrect answer is option 'A'. Can you explain this answer? for Class 12 2026 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A bar magnet of magnetic moment 1.5 J/T lies aligned with the direction of a uniform magnetic field of 0.22 T. What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction?a)0.66Jb)0.76J nCc)0.86Jd)0.56JCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar magnet of magnetic moment 1.5 J/T lies aligned with the direction of a uniform magnetic field of 0.22 T. What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction?a)0.66Jb)0.76J nCc)0.86Jd)0.56JCorrect answer is option 'A'. Can you explain this answer?.
A bar magnet of magnetic moment 1.5 J/T lies aligned with the direction of a uniform magnetic field of 0.22 T. What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction?a)0.66Jb)0.76J nCc)0.86Jd)0.56JCorrect answer is option 'A'. Can you explain this answer? for Class 12 2026 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A bar magnet of magnetic moment 1.5 J/T lies aligned with the direction of a uniform magnetic field of 0.22 T. What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction?a)0.66Jb)0.76J nCc)0.86Jd)0.56JCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar magnet of magnetic moment 1.5 J/T lies aligned with the direction of a uniform magnetic field of 0.22 T. What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment opposite to the field direction?a)0.66Jb)0.76J nCc)0.86Jd)0.56JCorrect answer is option 'A'. Can you explain this answer?.
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