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Two bodies of masses M1 and M2 are connected by a light string which passes over a frictionless massless pulley.If pulley is moving upward with uniform acceleration g/2. Then tension in the string will be 1) 3M1M2 / M1 +M2 *g. 2). M1+ M2/ 4M1M2* g. 3). 2M1M2/M1+M2 *g 4) M1M2/ M1 + M2 . Correct answer is 1 . Can you explain?
Most Upvoted Answer
Two bodies of masses M1 and M2 are connected by a light string which p...
Explanation:


The given system can be represented as shown below:


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The tension in the string can be calculated as follows:


Step 1: Find the acceleration of the blocks


Since the pulley is moving upward with an acceleration of g/2, the acceleration of the blocks can be calculated as follows:


a = (g/2) / (1+M2/M1)


Step 2: Find the tension in the string


Using Newton’s second law of motion, we can write the following equations of motion for the two blocks:


For block M1:


T - M1g = M1a


For block M2:


M2g - T = M2a


Solving the above two equations simultaneously, we get:


T = (2M1M2/M1+M2)g


Therefore, the correct option is 1.
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Two bodies of masses M1 and M2 are connected by a light string which p...
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Two bodies of masses M1 and M2 are connected by a light string which passes over a frictionless massless pulley.If pulley is moving upward with uniform acceleration g/2. Then tension in the string will be 1) 3M1M2 / M1 +M2 *g. 2). M1+ M2/ 4M1M2* g. 3). 2M1M2/M1+M2 *g 4) M1M2/ M1 + M2 . Correct answer is 1 . Can you explain?
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Two bodies of masses M1 and M2 are connected by a light string which passes over a frictionless massless pulley.If pulley is moving upward with uniform acceleration g/2. Then tension in the string will be 1) 3M1M2 / M1 +M2 *g. 2). M1+ M2/ 4M1M2* g. 3). 2M1M2/M1+M2 *g 4) M1M2/ M1 + M2 . Correct answer is 1 . Can you explain? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two bodies of masses M1 and M2 are connected by a light string which passes over a frictionless massless pulley.If pulley is moving upward with uniform acceleration g/2. Then tension in the string will be 1) 3M1M2 / M1 +M2 *g. 2). M1+ M2/ 4M1M2* g. 3). 2M1M2/M1+M2 *g 4) M1M2/ M1 + M2 . Correct answer is 1 . Can you explain? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bodies of masses M1 and M2 are connected by a light string which passes over a frictionless massless pulley.If pulley is moving upward with uniform acceleration g/2. Then tension in the string will be 1) 3M1M2 / M1 +M2 *g. 2). M1+ M2/ 4M1M2* g. 3). 2M1M2/M1+M2 *g 4) M1M2/ M1 + M2 . Correct answer is 1 . Can you explain?.
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