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 A spring of spring constant 5 × 103 N/m is stretched initally by 5 cm from the unstreched position. Then the work required to stretch it further by another 5 cm is                                             [AIEEE 2003]
  • a)
    12.50 N-m
  • b)
    18.75 N-m
  • c)
    25.00 N-m
  • d)
    6.25 N-m
Correct answer is option 'B'. Can you explain this answer?
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A spring of spring constant 5 × 103N/m is stretched initally by ...
work done in stretching a spring by a distance x is
W=½​kx2
where k is the spring constant.
work required to stretch the string by 10cm is
W1​=½​kx2=½ ​5×103(0.1)2=25J
work required to stretch the string by 5cm is
W2​=½​kx2=½ ​5×103(0.05)2=6.25J
Hence the work done in stretching it from 5cm to 10cm is
W1​−W2​=25−6.25=18.75J
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Most Upvoted Answer
A spring of spring constant 5 × 103N/m is stretched initally by ...
Work done is nothing but change in elastic potential energy. So,Work done = Final potential energy - Initial potential energyPotential energy at any instant = (kx^2)/2 where x is the extension from mean position.Initial extension = 5 cm and final extension = 10 cmAfter substituting you will get work done as 18.75 Nm
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A spring of spring constant 5 × 103N/m is stretched initally by ...
A spring of spring constant 5 refers to a spring that has a spring constant value of 5 N/m (Newton per meter).

The spring constant, also known as the force constant or stiffness, is a measure of how stiff or rigid a spring is. It tells us how much force is required to stretch or compress the spring by a certain amount.

In this case, a spring constant of 5 N/m means that a force of 5 Newtons is required to stretch or compress the spring by 1 meter. If a force of 10 Newtons is applied, the spring will stretch or compress by 2 meters, and so on.

The higher the spring constant, the stiffer the spring is. A spring with a higher spring constant will require more force to stretch or compress it compared to a spring with a lower spring constant.
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A spring of spring constant 5 × 103N/m is stretched initally by 5 cm from the unstreched position. Then the work required to stretch it further by another 5 cm is [AIEEE 2003]a)12.50 N-mb)18.75 N-mc)25.00 N-md)6.25 N-mCorrect answer is option 'B'. Can you explain this answer?
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A spring of spring constant 5 × 103N/m is stretched initally by 5 cm from the unstreched position. Then the work required to stretch it further by another 5 cm is [AIEEE 2003]a)12.50 N-mb)18.75 N-mc)25.00 N-md)6.25 N-mCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A spring of spring constant 5 × 103N/m is stretched initally by 5 cm from the unstreched position. Then the work required to stretch it further by another 5 cm is [AIEEE 2003]a)12.50 N-mb)18.75 N-mc)25.00 N-md)6.25 N-mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spring of spring constant 5 × 103N/m is stretched initally by 5 cm from the unstreched position. Then the work required to stretch it further by another 5 cm is [AIEEE 2003]a)12.50 N-mb)18.75 N-mc)25.00 N-md)6.25 N-mCorrect answer is option 'B'. Can you explain this answer?.
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