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Which of the following will exhibit geometrical isomerism? a) 1-phenyl-2-butene b) 3-phenyl-1-butene c) 2-phenyl-1- butene d) 1,1-diphenyl-1-propene?
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Which of the following will exhibit geometrical isomerism? a) 1-phenyl...
Geometrical Isomerism in Organic Molecules
Geometrical isomerism is a type of stereoisomerism that arises when there is restricted rotation around a double bond or a ring. It occurs due to the different spatial arrangements of substituents on either side of the double bond or within the ring. In order to determine which of the given compounds exhibit geometrical isomerism, let's analyze each option individually.
a) 1-phenyl-2-butene
In this compound, there is a double bond between the second and third carbon atoms, with a phenyl group attached to the first carbon. However, there are no substituents on either side of the double bond that are different from each other. Therefore, 1-phenyl-2-butene does not exhibit geometrical isomerism.
b) 3-phenyl-1-butene
In this compound, there is a double bond between the first and second carbon atoms, with a phenyl group attached to the third carbon. Similar to the previous compound, there are no substituents on either side of the double bond that are different from each other. Thus, 3-phenyl-1-butene also does not exhibit geometrical isomerism.
c) 2-phenyl-1-butene
This compound has a double bond between the first and second carbon atoms, and a phenyl group attached to the second carbon. Unlike the previous compounds, 2-phenyl-1-butene has two different substituents, a phenyl group and an alkyl group (CH3), on either side of the double bond. This arrangement allows for restricted rotation around the double bond, giving rise to geometrical isomerism. Therefore, 2-phenyl-1-butene exhibits geometrical isomerism.
d) 1,1-diphenyl-1-propene
In this compound, there is a double bond between the first and second carbon atoms, and two phenyl groups attached to the first carbon. Again, there are no substituents on either side of the double bond that are different from each other. Hence, 1,1-diphenyl-1-propene does not exhibit geometrical isomerism.
Conclusion
Out of the given options, only 2-phenyl-1-butene exhibits geometrical isomerism. The presence of two different substituents on either side of the double bond allows for restricted rotation and the formation of geometric isomers.
Geometrical isomerism is a type of stereoisomerism that arises when there is restricted rotation around a double bond or a ring. It occurs due to the different spatial arrangements of substituents on either side of the double bond or within the ring. In order to determine which of the given compounds exhibit geometrical isomerism, let's analyze each option individually.
a) 1-phenyl-2-butene
In this compound, there is a double bond between the second and third carbon atoms, with a phenyl group attached to the first carbon. However, there are no substituents on either side of the double bond that are different from each other. Therefore, 1-phenyl-2-butene does not exhibit geometrical isomerism.
b) 3-phenyl-1-butene
In this compound, there is a double bond between the first and second carbon atoms, with a phenyl group attached to the third carbon. Similar to the previous compound, there are no substituents on either side of the double bond that are different from each other. Thus, 3-phenyl-1-butene also does not exhibit geometrical isomerism.
c) 2-phenyl-1-butene
This compound has a double bond between the first and second carbon atoms, and a phenyl group attached to the second carbon. Unlike the previous compounds, 2-phenyl-1-butene has two different substituents, a phenyl group and an alkyl group (CH3), on either side of the double bond. This arrangement allows for restricted rotation around the double bond, giving rise to geometrical isomerism. Therefore, 2-phenyl-1-butene exhibits geometrical isomerism.
d) 1,1-diphenyl-1-propene
In this compound, there is a double bond between the first and second carbon atoms, and two phenyl groups attached to the first carbon. Again, there are no substituents on either side of the double bond that are different from each other. Hence, 1,1-diphenyl-1-propene does not exhibit geometrical isomerism.
Conclusion
Out of the given options, only 2-phenyl-1-butene exhibits geometrical isomerism. The presence of two different substituents on either side of the double bond allows for restricted rotation and the formation of geometric isomers.
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Which of the following will exhibit geometrical isomerism? a) 1-phenyl-2-butene b) 3-phenyl-1-butene c) 2-phenyl-1- butene d) 1,1-diphenyl-1-propene?
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Which of the following will exhibit geometrical isomerism? a) 1-phenyl-2-butene b) 3-phenyl-1-butene c) 2-phenyl-1- butene d) 1,1-diphenyl-1-propene? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which of the following will exhibit geometrical isomerism? a) 1-phenyl-2-butene b) 3-phenyl-1-butene c) 2-phenyl-1- butene d) 1,1-diphenyl-1-propene? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following will exhibit geometrical isomerism? a) 1-phenyl-2-butene b) 3-phenyl-1-butene c) 2-phenyl-1- butene d) 1,1-diphenyl-1-propene?.
Which of the following will exhibit geometrical isomerism? a) 1-phenyl-2-butene b) 3-phenyl-1-butene c) 2-phenyl-1- butene d) 1,1-diphenyl-1-propene? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which of the following will exhibit geometrical isomerism? a) 1-phenyl-2-butene b) 3-phenyl-1-butene c) 2-phenyl-1- butene d) 1,1-diphenyl-1-propene? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following will exhibit geometrical isomerism? a) 1-phenyl-2-butene b) 3-phenyl-1-butene c) 2-phenyl-1- butene d) 1,1-diphenyl-1-propene?.
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