Molarity and Molality of 93% C2SO4 Solution:

Given data:
- Percentage concentration of C2SO4 = 93%
- Density of the solution = 1.84 g/cc

To calculate the molarity and molality of the solution, we will follow these steps:

1. Determine the mass of C2SO4 in the solution:
Since the solution is 93% C2SO4 by weight, we can assume that 100 g of the solution contains 93 g of C2SO4. Therefore, the mass of C2SO4 in the solution can be calculated as:
Mass of C2SO4 = (93% / 100%) * mass of the solution

2. Calculate the volume of the solution:
Given that the density of the solution is 1.84 g/cc, we can use the formula:
Volume of the solution = Mass of the solution / Density of the solution

3. Calculate the molarity:
Molarity (M) is defined as the number of moles of solute per liter of solution. To determine the molarity, we need to find the number of moles of C2SO4 present in the solution. The formula is:
Molarity (M) = Moles of solute / Volume of solution (in liters)

4. Calculate the molality:
Molality (m) is defined as the number of moles of solute per kilogram of solvent. To calculate the molality, we need to determine the mass of the solvent (water) present in the solution. The formula is:
Molality (m) = Moles of solute / Mass of solvent (in kg)

Let's perform the calculations:

Mass of C2SO4 = (93% / 100%) * mass of the solution
Volume of the solution = Mass of the solution / Density of the solution
Moles of C2SO4 = Mass of C2SO4 / Molar mass of C2SO4
Molarity (M) = Moles of C2SO4 / Volume of solution (in liters)
Molality (m) = Moles of C2SO4 / Mass of solvent (in kg)

Make sure to substitute the appropriate values for the variables in the equations above to find the final values of molarity and molality.

By following these steps, you will be able to calculate the molarity and molality of the given 93% C2SO4 solution.

Density =1.84gm/cm3
mass of solution = 1840gm
Volume of solution =1L
Molar mass(C2SO4) =2×12+32×1+4×16=120gm/mol
mass(C2SO4)= 0.93(1840gm)=1711.2gm
mass(H2O) = 0.07×1840gm = 128.8gm=0.1288Kg
nO mole=mass(C2SO4)/Molar mass(C2SO4)
n =1711.2gm/(120gm/mol)=14.26mol
Molarity = n/V =14.26mol/1L=14.26M
morality = n/m(Kg) = 14.26mol/0.1288Kg
morality = 110.7mol/kg