285 is summation of 3 numbers. Ratio between 2ndand 3rdnumbers is 6:5....
Given information:
- Sum of three numbers is 285
- Ratio between 2nd and 3rd numbers is 6:5
- Ratio between 1st and 2nd numbers is 3:7
To find: The 3rd number
Solution:
Let's assume the three numbers to be x, y, and z
- Sum of three numbers is given as 285, so we can write an equation as:
x + y + z = 285
- Ratio between 2nd and 3rd numbers is given as 6:5, which means:
y/z = 6/5
or, y = (6/5)z
- Ratio between 1st and 2nd numbers is given as 3:7, which means:
x/y = 3/7
or, x = (3/7)y
Substituting the value of y in terms of z from the first equation, we get:
x = (3/7)(6/5)z
or, x = (18/35)z
Now, we can substitute the values of x and y in the first equation and simplify to get the value of z:
(18/35)z + (6/5)z + z = 285
(126/35)z = 285
z = (285*35)/126
z = 105
Therefore, the 3rd number is 105, which is option D.
285 is summation of 3 numbers. Ratio between 2ndand 3rdnumbers is 6:5....
Given:
- Sum of 3 numbers = 285
- Ratio between 2nd and 3rd numbers = 6:5
- Ratio between 1st and 2nd numbers = 3:7
To find: The 3rd number
Solution:
Let the three numbers be a, b, and c.
From the given ratios, we can write:
b:c = 6:5 (1)
a:b = 3:7 (2)
We know that the sum of the three numbers is 285.
So, a + b + c = 285
From equation (2), we can write:
a/b = 3/7
=> a = (3/7) * b
Substituting this value of a in the above equation, we get:
(3/7) * b + b + c = 285
=> (10/7) * b + c = 285
From equation (1), we know that b/c = 6/5
=> b = (6/5) * c
Substituting this value of b in the above equation, we get:
(10/7) * (6/5) * c + c = 285
=> (12/7) * c + c = 285
=> (19/7) * c = 285
=> c = (285 * 7) / 19
=> c = 105
Therefore, the 3rd number is 105, which is option (D).