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During the adsorption of Krypton on activated charcoal at low temperature 
  • a)
    ΔH < 0 and ΔS < 0
  • b)
    ΔH > 0 and ΔS < 0
  • c)
    ΔH > 0 and ΔS > 0
  • d)
    ΔH < 0 and ΔS > 0
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
During the adsorption of Krypton on activated charcoal at low temperat...
Correct answer is option A
During the adsorption of krypton on activated charcoal at low temperature.
ΔH<0 and ΔS<0.
Since adsorption is an exothermic process, the enthalpy change is negative. Heat is given out during the process.
The krypton gas adsorbed on activated charcoal is more ordered than unadsorbed krypton gas. Hence, the process occurs with a decrease in entropy. 
In other words, the entropy change is negative for the process.
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Most Upvoted Answer
During the adsorption of Krypton on activated charcoal at low temperat...
Generally adsorption is an exothermic process so enthalpy change must be negative and adsorption involves decrease in irregular movement of the molecules so entropy decreases
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Community Answer
During the adsorption of Krypton on activated charcoal at low temperat...
Charcoal adsorption beds are commonly used to remove radioactive noble gases from contaminated gas streams. The design of such beds requires the adsorption coefficient for the noble gas. Here an extension of the Dubinin-Radushkevich theory of adsorption is developed to correlate the effects of temperature, pressure, concentration, and carrier gas on the adsorption coefficients of krypton, xenon, and argon on activated carbon. This model is validated with previously published adsorption measurements. It accurately predicts the equilibrium adsorption coefficient at any temperature and pressure if the potential energies of adsorption, the micropore volume, and the van der Waals constants of the gases are known
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During the adsorption of Krypton on activated charcoal at low temperaturea)ΔH < 0 and ΔS < 0b)ΔH > 0 and ΔS < 0c)ΔH > 0 and ΔS > 0d)ΔH < 0 and ΔS > 0Correct answer is option 'A'. Can you explain this answer?
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