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Number of 5 digit numbers divisible by 25 that can be formed using only the digits 1,2,3,4,5 & 0 taken five at a time a)-2 b)-32 c)-42 d)-52?
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Number of 5 digit numbers divisible by 25 that can be formed using onl...
A number will be divisible by 25 if it ends with 25 (or) 50 (or) 75 (or) 00. But here we don't have any 7 and only one 0 so the lat two cases are not possible. Now the last two digits must be fixed and the first three can be filled accordingly. Remember that the first digit (a) cannot be zero since we need a 5 digit number. The number below the under brace tells us how many numbers can be filled in that position,
In the first case we haven't fixed 0 so there are only three possible ways in filling "a" (1,3, or 4). But in the next case we have fixed 0 so the first digit can be anything from the remaining four numbers.
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Number of 5 digit numbers divisible by 25 that can be formed using onl...
To form a 5-digit number divisible by 25, the last two digits must be either 25 or 50.
Case 1: Last two digits are 25
In this case, the first three digits can be any of the remaining 3 digits (1, 2, 3, 4, 5) and the last two digits are fixed. Therefore, there are $3 \cdot 4 \cdot 5 = 60$ numbers.
Case 2: Last two digits are 50
In this case, the first three digits can be any of the remaining 3 digits (1, 2, 3, 4, 5) and the last two digits are fixed. Therefore, there are $3 \cdot 4 \cdot 5 = 60$ numbers.
Hence, the total number of 5-digit numbers divisible by 25 that can be formed using only the digits 1, 2, 3, 4, 5 is $60 + 60 = \boxed{120}$.
Case 1: Last two digits are 25
In this case, the first three digits can be any of the remaining 3 digits (1, 2, 3, 4, 5) and the last two digits are fixed. Therefore, there are $3 \cdot 4 \cdot 5 = 60$ numbers.
Case 2: Last two digits are 50
In this case, the first three digits can be any of the remaining 3 digits (1, 2, 3, 4, 5) and the last two digits are fixed. Therefore, there are $3 \cdot 4 \cdot 5 = 60$ numbers.
Hence, the total number of 5-digit numbers divisible by 25 that can be formed using only the digits 1, 2, 3, 4, 5 is $60 + 60 = \boxed{120}$.
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Number of 5 digit numbers divisible by 25 that can be formed using only the digits 1,2,3,4,5 & 0 taken five at a time a)-2 b)-32 c)-42 d)-52?
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Number of 5 digit numbers divisible by 25 that can be formed using only the digits 1,2,3,4,5 & 0 taken five at a time a)-2 b)-32 c)-42 d)-52? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Number of 5 digit numbers divisible by 25 that can be formed using only the digits 1,2,3,4,5 & 0 taken five at a time a)-2 b)-32 c)-42 d)-52? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Number of 5 digit numbers divisible by 25 that can be formed using only the digits 1,2,3,4,5 & 0 taken five at a time a)-2 b)-32 c)-42 d)-52?.
Number of 5 digit numbers divisible by 25 that can be formed using only the digits 1,2,3,4,5 & 0 taken five at a time a)-2 b)-32 c)-42 d)-52? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Number of 5 digit numbers divisible by 25 that can be formed using only the digits 1,2,3,4,5 & 0 taken five at a time a)-2 b)-32 c)-42 d)-52? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Number of 5 digit numbers divisible by 25 that can be formed using only the digits 1,2,3,4,5 & 0 taken five at a time a)-2 b)-32 c)-42 d)-52?.
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