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Potential energy of a particle varies with its position as U ( x ) = x 4 /4-x2/2. J. If the total mechanical energy of the particle is 2J. Then the maximum speed of the particle in m / s is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Potential energy of a particle varies with its position as U ( x ) = x 4 /4-x2/2. J. If the total mechanical energy of the particle is 2J. Then the maximum speed of the particle in m / s is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Potential energy of a particle varies with its position as U ( x ) = x 4 /4-x2/2. J. If the total mechanical energy of the particle is 2J. Then the maximum speed of the particle in m / s is?.

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