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Calculate the voltage needed to balance an oil drop carrying 10 electrons when located between the plates of a capacitor which are 5 mm apart. Mass of oil drop is 3 microgram
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Calculate the voltage needed to balance an oil drop carrying 10 electr...
The gravitational force on the oil drop = mg = 3 x 10-16 x 10 = 3 x 10-15 N.Magnitude of the electrostatic force needed balance this force is given byE = mg/10e = (3 x 10-15) / (10 x 1.6 x 10-19) = 0.1875 x 104 V/m.Voltage across the places of the capacitor is then given byV = Ed = 0.1875 x 104 x 5 x 10-3 = 9.375 Volts.
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Calculate the voltage needed to balance an oil drop carrying 10 electr...
Calculating the Voltage to Balance an Oil Drop

To calculate the voltage needed to balance an oil drop carrying 10 electrons, we need to use the Millikan oil drop experiment. This experiment involves measuring the electric field between two plates of a capacitor to determine the charge of an oil drop suspended between them.

Steps to Follow

1. Calculate the mass of the oil drop: Given that the mass of the oil drop is 3 micrograms, we convert this to kilograms by dividing by 10^12.

3 micrograms = 3 x 10^-12 kg

2. Calculate the charge of the oil drop: The charge of the oil drop can be calculated using the number of electrons it carries.

Charge of 1 electron = 1.6 x 10^-19 C

Charge of 10 electrons = 1.6 x 10^-19 C x 10 = 1.6 x 10^-18 C

3. Measure the electric field between the plates of the capacitor: The electric field between the plates of the capacitor can be calculated using the distance between the plates and the voltage applied across them.

Distance between plates = 5 mm = 5 x 10^-3 m

Electric field = Voltage / distance between plates

4. Calculate the voltage needed to balance the oil drop: Once we have the charge of the oil drop and the electric field between the plates, we can use the following equation to calculate the voltage needed to balance the oil drop:

mg = qE

where m is the mass of the oil drop, g is the acceleration due to gravity, q is the charge of the oil drop, and E is the electric field between the plates.

Solving for voltage, we get:

V = (mg) / qd

where d is the distance between the plates.

Plugging in the values we have calculated, we get:

V = (3 x 10^-12 kg x 9.81 m/s^2) / (1.6 x 10^-18 C x 5 x 10^-3 m)

V = 1.14 x 10^4 V

Therefore, the voltage needed to balance an oil drop carrying 10 electrons between the plates of a capacitor which are 5 mm apart is 1.14 x 10^4 V.
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Calculate the voltage needed to balance an oil drop carrying 10 electrons when located between the plates of a capacitor which are 5 mm apart. Mass of oil drop is 3 microgram
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