Calculate the work done when 1.0 mol of water at 373 k vaporize against an atmospheric pressure of 1.0 atmospher . assume ideal gas behaviour. please explain the answers.?

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Calculate the work done when 1.0 mol of water at 373 k vaporize against an atmospheric pressure of 1.0 atmospher . assume ideal gas behaviour. please explain the answers.?

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Calculate the work done when 1.0 mol of water at 373 k vaporize agains...

We know,

PV=nRT

V=nRT/P

V= 1X0.0821X373/1=30.6L=30.6X10-3m3

Volume of liquid water can be taken negligible and thus ΔV=30.6L

W=-P ΔV=-101325X30.6 X10-3m3=-3100J

Negative sign indicates that work is done by the system.

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