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A particle moving in one dimension with aconstant acceleration of 2ms2 is observed to cover a distance of 5m during aparticular interval of 1s.The distance coverd by the particle in next !s interval is?
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A particle moving in one dimension with aconstant acceleration of 2ms2...
Given:
Acceleration (a) = 2 m/s^2
Distance covered in 1st interval (d1) = 5 m
Time taken in 1st interval (t1) = 1 s
To Find:
Distance covered in the next interval (d2)
Explanation:
To solve this problem, we can use the kinematic equation:
d = ut + 0.5at^2
Where:
d = distance covered
u = initial velocity
t = time
a = acceleration
Step 1: Finding Initial Velocity (u)
Since the initial velocity is not given, we need to find it using the given information. From the given data, we can determine the initial velocity using the equation:
d1 = ut1 + 0.5at1^2
Substituting the known values:
5 = u(1) + 0.5(2)(1)^2
Simplifying the equation:
5 = u + 1
Rearranging the equation to solve for u:
u = 5 - 1
u = 4 m/s
So, the initial velocity (u) is 4 m/s.
Step 2: Finding Distance in the Next Interval (d2)
To find the distance covered in the next interval (d2), we need to use the equation again:
d2 = ut2 + 0.5at2^2
Where:
t2 = 1 s (as given)
Substituting the known values:
d2 = (4)(1) + 0.5(2)(1)^2
Simplifying the equation:
d2 = 4 + 0.5(2)(1)
d2 = 4 + 1
d2 = 5 m
Therefore, the distance covered by the particle in the next 1-second interval is 5 meters.
Summary:
The particle, with a constant acceleration of 2 m/s^2, covered a distance of 5 meters in the first 1-second interval. By using the kinematic equation, we found that the initial velocity is 4 m/s. Then, using the same equation, we determined that the particle covers a distance of 5 meters in the next 1-second interval as well.
Acceleration (a) = 2 m/s^2
Distance covered in 1st interval (d1) = 5 m
Time taken in 1st interval (t1) = 1 s
To Find:
Distance covered in the next interval (d2)
Explanation:
To solve this problem, we can use the kinematic equation:
d = ut + 0.5at^2
Where:
d = distance covered
u = initial velocity
t = time
a = acceleration
Step 1: Finding Initial Velocity (u)
Since the initial velocity is not given, we need to find it using the given information. From the given data, we can determine the initial velocity using the equation:
d1 = ut1 + 0.5at1^2
Substituting the known values:
5 = u(1) + 0.5(2)(1)^2
Simplifying the equation:
5 = u + 1
Rearranging the equation to solve for u:
u = 5 - 1
u = 4 m/s
So, the initial velocity (u) is 4 m/s.
Step 2: Finding Distance in the Next Interval (d2)
To find the distance covered in the next interval (d2), we need to use the equation again:
d2 = ut2 + 0.5at2^2
Where:
t2 = 1 s (as given)
Substituting the known values:
d2 = (4)(1) + 0.5(2)(1)^2
Simplifying the equation:
d2 = 4 + 0.5(2)(1)
d2 = 4 + 1
d2 = 5 m
Therefore, the distance covered by the particle in the next 1-second interval is 5 meters.
Summary:
The particle, with a constant acceleration of 2 m/s^2, covered a distance of 5 meters in the first 1-second interval. By using the kinematic equation, we found that the initial velocity is 4 m/s. Then, using the same equation, we determined that the particle covers a distance of 5 meters in the next 1-second interval as well.
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A particle moving in one dimension with aconstant acceleration of 2ms2...
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A particle moving in one dimension with aconstant acceleration of 2ms2 is observed to cover a distance of 5m during aparticular interval of 1s.The distance coverd by the particle in next !s interval is?
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A particle moving in one dimension with aconstant acceleration of 2ms2 is observed to cover a distance of 5m during aparticular interval of 1s.The distance coverd by the particle in next !s interval is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle moving in one dimension with aconstant acceleration of 2ms2 is observed to cover a distance of 5m during aparticular interval of 1s.The distance coverd by the particle in next !s interval is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle moving in one dimension with aconstant acceleration of 2ms2 is observed to cover a distance of 5m during aparticular interval of 1s.The distance coverd by the particle in next !s interval is?.
A particle moving in one dimension with aconstant acceleration of 2ms2 is observed to cover a distance of 5m during aparticular interval of 1s.The distance coverd by the particle in next !s interval is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle moving in one dimension with aconstant acceleration of 2ms2 is observed to cover a distance of 5m during aparticular interval of 1s.The distance coverd by the particle in next !s interval is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle moving in one dimension with aconstant acceleration of 2ms2 is observed to cover a distance of 5m during aparticular interval of 1s.The distance coverd by the particle in next !s interval is?.
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