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The equation of the bisector of the acute angle between the lines 3x–4y+7 = 0 and 12x+5y–2 = 0 is
  • a)
     21x+77y–101 = 0
  • b)
    11x+3y+20 = 0
  • c)
    21x–7y+3 =0
  • d)
    11x–3y+9 = 0
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The equation of the bisector of the acute angle between the lines 3x–4...
Given Lines:
3x – 4y + 7 = 0
12x + 5y – 2 = 0

Finding Slopes of Given Lines:
Slope of the first line = 3/4
Slope of the second line = -12/5

Calculating Slope of Bisector:
Slope of bisector = -1 * (m1 + m2) / (m1 * m2)
Slope of bisector = -1 * (3/4 - 12/5) / (3/4 * -12/5)
Slope of bisector = -1 * (-33/20) / (-9/20)
Slope of bisector = 11/3

Equation of Bisector:
Using point-slope form, the equation of the bisector passing through the point of intersection of the given lines (intersection point can be calculated) with slope 11/3:
Equation of bisector: y – y1 = m(x – x1)
Equation of bisector: y – y1 = (11/3)(x – x1)
After substituting the intersection point, the equation simplifies to:
11x – 3y + 9 = 0
Therefore, the correct answer is option 'D': 11x – 3y + 9 = 0.
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Community Answer
The equation of the bisector of the acute angle between the lines 3x–4...
(a1x +b1y)/√(a1^2 + b1^2) = + - (a2x +b2y)/√(a2^2+ b2^2)
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The equation of the bisector of the acute angle between the lines 3x–4y+7 = 0 and 12x+5y–2 = 0 isa)21x+77y–101 = 0 b)11x+3y+20 = 0c) 21x–7y+3 =0d)11x–3y+9 = 0Correct answer is option 'D'. Can you explain this answer?
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The equation of the bisector of the acute angle between the lines 3x–4y+7 = 0 and 12x+5y–2 = 0 isa)21x+77y–101 = 0 b)11x+3y+20 = 0c) 21x–7y+3 =0d)11x–3y+9 = 0Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equation of the bisector of the acute angle between the lines 3x–4y+7 = 0 and 12x+5y–2 = 0 isa)21x+77y–101 = 0 b)11x+3y+20 = 0c) 21x–7y+3 =0d)11x–3y+9 = 0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of the bisector of the acute angle between the lines 3x–4y+7 = 0 and 12x+5y–2 = 0 isa)21x+77y–101 = 0 b)11x+3y+20 = 0c) 21x–7y+3 =0d)11x–3y+9 = 0Correct answer is option 'D'. Can you explain this answer?.
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