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An amount of solid NH4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield NH3 and H2S gases in the flask.
When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm. The equilibrium constant for the decomposition of NH4HS at this temperature is
(AIEEE 2005)
  • a)
    0.11
  • b)
    0.17
  • c)
    0.18
  • d)
    0.30
Correct answer is option 'A'. Can you explain this answer?
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Equilibrium Constant Calculation for Decomposition of NH4HS:

Given Data:
- Initial pressure of ammonia gas (NH3): 0.50 atm
- Total pressure at equilibrium: 0.84 atm

Equilibrium Constant (Kp):
- The equilibrium constant (Kp) for the decomposition of NH4HS can be calculated using the expression:
Kp = (P(NH3) * P(H2S)) / P(NH4HS)

Pressure Calculation:
- At equilibrium, the total pressure is the sum of the partial pressures of NH3 and H2S:
P(total) = P(NH3) + P(H2S)

Partial Pressure Calculation:
- Since NH4HS decomposes into NH3 and H2S, the initial pressure of NH4HS will decrease by 'x', and the partial pressures of NH3 and H2S will increase by 'x'.
- Therefore, at equilibrium:
P(NH4HS) = 0.50 - x
P(NH3) = x
P(H2S) = x

Equilibrium Pressure Calculation:
- Given that the total pressure at equilibrium is 0.84 atm, we can substitute the partial pressures into the total pressure equation:
0.84 = 0.50 + 2x
2x = 0.34
x = 0.17 atm

Equilibrium Constant Calculation:
- Now, substitute the values of x into the equilibrium constant expression:
Kp = (0.17 * 0.17) / (0.50 - 0.17) = 0.11
Therefore, the equilibrium constant for the decomposition of NH4HS at this temperature is 0.11 (option 'A').
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An amount of solid NH4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield NH3 and H2S gases in the flask.When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm. The equilibrium constant for the decomposition of NH4HS at this temperature is(AIEEE2005)a)0.11b)0.17c)0.18d)0.30Correct answer is option 'A'. Can you explain this answer?
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An amount of solid NH4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield NH3 and H2S gases in the flask.When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm. The equilibrium constant for the decomposition of NH4HS at this temperature is(AIEEE2005)a)0.11b)0.17c)0.18d)0.30Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An amount of solid NH4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield NH3 and H2S gases in the flask.When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm. The equilibrium constant for the decomposition of NH4HS at this temperature is(AIEEE2005)a)0.11b)0.17c)0.18d)0.30Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An amount of solid NH4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield NH3 and H2S gases in the flask.When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm. The equilibrium constant for the decomposition of NH4HS at this temperature is(AIEEE2005)a)0.11b)0.17c)0.18d)0.30Correct answer is option 'A'. Can you explain this answer?.
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