Pressure of 10 moles of an ideal gas is changed from 2atm to 1atm against constant external pressure without change in temperature. If surrounding temperature (300K)and pressure (1atm) always remains constant then calculate total entropy change for given process?

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Pressure of 10 moles of an ideal gas is changed from 2atm to 1atm against constant external pressure without change in temperature(300k) and pressure (1atm) always remains constant then calculate total entropy change?

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A certain mass of gas is expanded from bracket 1 l 10 ATM bracket close to bracket 4l, 5atm bracket close against a constant external pressure of 1 ATM if initial temperature of gas is 300 Kelvin and the heat capacity of process is 50 joules less degree Celsius then the enthalpy change during the processes?

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A gaseous sample is generally allowed to do only expansion/compression type of work against its surroundings. The work done in case of an irreversible expansion (in the intermediate stages, of expansion/compression the states of gases are not define d). The work done can be calculated usingdW = NextdVwhile in case of reversible process the work done can be calculated using dw = PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process.Since d w = P d V so magnitude of worked one can also be calculated by, calculating the area under the PV curve of the reversible process in PV diagram.Q.Two samples (initially under same states) of an ideal gas are first allowed to expand to double their volume using irreversible isothermal expansion against constant external pressure, then samples are returned back to their original volume first by reversible adiabatic process and second by reversible process having equation PV2 = constant then

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The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. Mechanical equilibrium of the atmosphere requires that the pressure decreases with altitude according to . Assuming free fall acceleration to be uniform, then lapse rate is given by

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2.8g of N2 gas at 300k and 20 atm was allowed to expand isothermally against a constant external pressure of 1 atm.calculate W for the gas?

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Pressure of 10 moles of an ideal gas is changed from 2atm to 1atm against constant external pressure without change in temperature. If surrounding temperature (300K)and pressure (1atm) always remains constant then calculate total entropy change for given process? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Pressure of 10 moles of an ideal gas is changed from 2atm to 1atm against constant external pressure without change in temperature. If surrounding temperature (300K)and pressure (1atm) always remains constant then calculate total entropy change for given process? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Pressure of 10 moles of an ideal gas is changed from 2atm to 1atm against constant external pressure without change in temperature. If surrounding temperature (300K)and pressure (1atm) always remains constant then calculate total entropy change for given process?.

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