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If |x³-9x²+26x-24| is a prime no. then the no. of possible integral value of x is?
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If |x³-9x²+26x-24| is a prime no. then the no. of possible integral va...
Solution:

Given expression is |x³-9x²+26x-24|

Let's factorize the expression:

|x³-9x²+26x-24| = |x²(x-9)+2(x-9)|

= |(x-9)(x²+2)|

Now, for the expression to be a prime number, one of the factors must be equal to 1 and the other factor must be the prime number.

Case 1: x-9 = 1

This gives us x = 10

Substituting x = 10 in the expression, we get:

|10²+2| = 102 which is a prime number.

Case 2: x²+2 = 1

This gives us x = ±i√2

However, we are looking for integral values of x, which excludes complex numbers.

Therefore, the only possible value of x is 10.

Conclusion:

The only possible integral value of x that makes the expression a prime number is x = 10.
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If |x³-9x²+26x-24| is a prime no. then the no. of possible integral value of x is?
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