Class 11 Exam > Class 11 Questions > Out of a pair of identical springs of spring ...
Start Learning for Free
Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:
- a)1.2 J
- b)4 J
- c)zero
- d)12 J
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Out of a pair of identical springs of spring constants 240 N/m, one is...
P.E. stored in a spring = 1/2Kx2
where x is the extension or compression. In both cases, work is done on the spring.
∴ For the same x, the same potential energy will be stored in the springs.
∴ The difference between the energies is zero.
where x is the extension or compression. In both cases, work is done on the spring.
∴ For the same x, the same potential energy will be stored in the springs.
∴ The difference between the energies is zero.
Most Upvoted Answer
Out of a pair of identical springs of spring constants 240 N/m, one is...
As both the springs are identical, equal displacement produces equal amount of p.e in them though opposite in direction.Hence their difference is zero
Free Test
FREE
| Start Free Test |
Community Answer
Out of a pair of identical springs of spring constants 240 N/m, one is...
Given:
Spring constant, k = 240 N/m
Compression of one spring = 10 cm = 0.1 m
Stretching of the other spring = 10 cm = 0.1 m
Potential Energy of a spring is given by the formula:
P.E. = (1/2)kx^2
where k is the spring constant and x is the displacement from the equilibrium position.
Calculating the P.E. for the compressed spring:
P.E.1 = (1/2)kx^2 = (1/2)(240)(0.1)^2 = 1.2 J
Calculating the P.E. for the stretched spring:
P.E.2 = (1/2)kx^2 = (1/2)(240)(0.1)^2 = 1.2 J
Therefore, the potential energy stored in both springs is the same, and the difference in P.E. is zero.
Explanation:
The potential energy stored in a spring depends on its spring constant and the displacement from its equilibrium position. In this case, both springs have the same spring constant and are displaced by the same amount, but in opposite directions.
When a spring is compressed or stretched, it stores potential energy. The potential energy is proportional to the square of the displacement. Since the displacement is the same for both springs, the potential energy stored in them will be the same.
Hence, the difference in potential energy stored in the two springs is zero.
Spring constant, k = 240 N/m
Compression of one spring = 10 cm = 0.1 m
Stretching of the other spring = 10 cm = 0.1 m
Potential Energy of a spring is given by the formula:
P.E. = (1/2)kx^2
where k is the spring constant and x is the displacement from the equilibrium position.
Calculating the P.E. for the compressed spring:
P.E.1 = (1/2)kx^2 = (1/2)(240)(0.1)^2 = 1.2 J
Calculating the P.E. for the stretched spring:
P.E.2 = (1/2)kx^2 = (1/2)(240)(0.1)^2 = 1.2 J
Therefore, the potential energy stored in both springs is the same, and the difference in P.E. is zero.
Explanation:
The potential energy stored in a spring depends on its spring constant and the displacement from its equilibrium position. In this case, both springs have the same spring constant and are displaced by the same amount, but in opposite directions.
When a spring is compressed or stretched, it stores potential energy. The potential energy is proportional to the square of the displacement. Since the displacement is the same for both springs, the potential energy stored in them will be the same.
Hence, the difference in potential energy stored in the two springs is zero.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer?
Question Description
Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer?.
Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup