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Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:
- a)1.2 J
- b)4 J
- c)zero
- d)12 J
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Out of a pair of identical springs of spring constants 240 N/m, one is...
P.E. stored in a spring = 1/2Kx2
where x is the extension or compression. In both cases, work is done on the spring.
∴ For the same x, the same potential energy will be stored in the springs.
∴ The difference between the energies is zero.
where x is the extension or compression. In both cases, work is done on the spring.
∴ For the same x, the same potential energy will be stored in the springs.
∴ The difference between the energies is zero.
Most Upvoted Answer
Out of a pair of identical springs of spring constants 240 N/m, one is...
As both the springs are identical, equal displacement produces equal amount of p.e in them though opposite in direction.Hence their difference is zero
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Community Answer
Out of a pair of identical springs of spring constants 240 N/m, one is...
Given:
Spring constant, k = 240 N/m
Compression of one spring = 10 cm = 0.1 m
Stretching of the other spring = 10 cm = 0.1 m
Potential Energy of a spring is given by the formula:
P.E. = (1/2)kx^2
where k is the spring constant and x is the displacement from the equilibrium position.
Calculating the P.E. for the compressed spring:
P.E.1 = (1/2)kx^2 = (1/2)(240)(0.1)^2 = 1.2 J
Calculating the P.E. for the stretched spring:
P.E.2 = (1/2)kx^2 = (1/2)(240)(0.1)^2 = 1.2 J
Therefore, the potential energy stored in both springs is the same, and the difference in P.E. is zero.
Explanation:
The potential energy stored in a spring depends on its spring constant and the displacement from its equilibrium position. In this case, both springs have the same spring constant and are displaced by the same amount, but in opposite directions.
When a spring is compressed or stretched, it stores potential energy. The potential energy is proportional to the square of the displacement. Since the displacement is the same for both springs, the potential energy stored in them will be the same.
Hence, the difference in potential energy stored in the two springs is zero.
Spring constant, k = 240 N/m
Compression of one spring = 10 cm = 0.1 m
Stretching of the other spring = 10 cm = 0.1 m
Potential Energy of a spring is given by the formula:
P.E. = (1/2)kx^2
where k is the spring constant and x is the displacement from the equilibrium position.
Calculating the P.E. for the compressed spring:
P.E.1 = (1/2)kx^2 = (1/2)(240)(0.1)^2 = 1.2 J
Calculating the P.E. for the stretched spring:
P.E.2 = (1/2)kx^2 = (1/2)(240)(0.1)^2 = 1.2 J
Therefore, the potential energy stored in both springs is the same, and the difference in P.E. is zero.
Explanation:
The potential energy stored in a spring depends on its spring constant and the displacement from its equilibrium position. In this case, both springs have the same spring constant and are displaced by the same amount, but in opposite directions.
When a spring is compressed or stretched, it stores potential energy. The potential energy is proportional to the square of the displacement. Since the displacement is the same for both springs, the potential energy stored in them will be the same.
Hence, the difference in potential energy stored in the two springs is zero.
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Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:a)1.2 Jb)4 Jc)zerod)12 JCorrect answer is option 'C'. Can you explain this answer?
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