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The standard enthalpy of formation of NH3 is -46.0 kJ mol-1 . If the enthalpy of formation of H2 from its atoms is -436 kJ mol-1 and that of N2 is -712 kJ mol-1 , the average bond enthalpy of N - H bond in           [AIEEE 2010]
  • a)
    -1102 kJ mol-1
  • b)
    -964 kJ mol-1
  • c)
    +352 kJ mol-1
  • d)
    +1056 kJ mol-1
Correct answer is option 'C'. Can you explain this answer?
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The standard enthalpy of formation of NH3 is -46.0 kJ mol-1 . If the e...
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The standard enthalpy of formation of NH3 is -46.0 kJ mol-1 . If the enthalpy of formation of H2 from its atoms is -436 kJ mol-1 and that of N2 is -712 kJ mol-1 , the average bond enthalpy of N - H bond in [AIEEE 2010]a)-1102 kJ mol-1b)-964 kJ mol-1c)+352 kJ mol-1d)+1056 kJ mol-1Correct answer is option 'C'. Can you explain this answer?
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The standard enthalpy of formation of NH3 is -46.0 kJ mol-1 . If the enthalpy of formation of H2 from its atoms is -436 kJ mol-1 and that of N2 is -712 kJ mol-1 , the average bond enthalpy of N - H bond in [AIEEE 2010]a)-1102 kJ mol-1b)-964 kJ mol-1c)+352 kJ mol-1d)+1056 kJ mol-1Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The standard enthalpy of formation of NH3 is -46.0 kJ mol-1 . If the enthalpy of formation of H2 from its atoms is -436 kJ mol-1 and that of N2 is -712 kJ mol-1 , the average bond enthalpy of N - H bond in [AIEEE 2010]a)-1102 kJ mol-1b)-964 kJ mol-1c)+352 kJ mol-1d)+1056 kJ mol-1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard enthalpy of formation of NH3 is -46.0 kJ mol-1 . If the enthalpy of formation of H2 from its atoms is -436 kJ mol-1 and that of N2 is -712 kJ mol-1 , the average bond enthalpy of N - H bond in [AIEEE 2010]a)-1102 kJ mol-1b)-964 kJ mol-1c)+352 kJ mol-1d)+1056 kJ mol-1Correct answer is option 'C'. Can you explain this answer?.
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