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Find the approximate value of f(10.01) where f(x) = 5x2 +6x + 3
- a)564.06
- b)564.01
- c)563.00
- d)563.01
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Find the approximate value off(10.01)where f(x) = 5x2 +6x + 3a)...
f(x) = 5x2 +6x + 3
f(10.01) = 5*(10.01)2 + 6*(10.01) + 3
To find (10.01)2
Let p=10, Δp=0.01
y=p2 = 100
y+Δy = (p+ Δp)2 = (10.01)2
Δy = (dy/dp) * Δp
Δy = 2*p* Δx
Δy = 2*10* 0.01
Δy = 20 * 0.01
Δy = 0.2
So, (10.01)2 = y + Δy
= 100.2
So,
f(10.01) = 5*(100.2) + 6*(10.01) + 3
= 501 + 60.06 + 3
= 564.06
f(10.01) = 5*(10.01)2 + 6*(10.01) + 3
To find (10.01)2
Let p=10, Δp=0.01
y=p2 = 100
y+Δy = (p+ Δp)2 = (10.01)2
Δy = (dy/dp) * Δp
Δy = 2*p* Δx
Δy = 2*10* 0.01
Δy = 20 * 0.01
Δy = 0.2
So, (10.01)2 = y + Δy
= 100.2
So,
f(10.01) = 5*(100.2) + 6*(10.01) + 3
= 501 + 60.06 + 3
= 564.06
Most Upvoted Answer
Find the approximate value off(10.01)where f(x) = 5x2 +6x + 3a)...
f(x) = 5x2 +6x + 3
f(10.01) = 5*(10.01)2 + 6*(10.01) + 3
To find (10.01)2
Let p=10, Δp=0.01
y=p2 = 100
y+Δy = (p+ Δp)2 = (10.01)2
Δy = (dy/dp) * Δp
Δy = 2*p* Δx
Δy = 2*10* 0.01
Δy = 20 * 0.01
Δy = 0.2
So, (10.01)2 = y + Δy
= 100.2
So,
f(10.01) = 5*(100.2) + 6*(10.01) + 3
= 501 + 60.06 + 3
= 564.06
f(10.01) = 5*(10.01)2 + 6*(10.01) + 3
To find (10.01)2
Let p=10, Δp=0.01
y=p2 = 100
y+Δy = (p+ Δp)2 = (10.01)2
Δy = (dy/dp) * Δp
Δy = 2*p* Δx
Δy = 2*10* 0.01
Δy = 20 * 0.01
Δy = 0.2
So, (10.01)2 = y + Δy
= 100.2
So,
f(10.01) = 5*(100.2) + 6*(10.01) + 3
= 501 + 60.06 + 3
= 564.06
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Community Answer
Find the approximate value off(10.01)where f(x) = 5x2 +6x + 3a)...
Explanation:
Given function:
f(x) = 5x^2 + 6x + 3
Value to be calculated:
f(10.01)
Calculation:
Substitute x = 10.01 into the given function:
f(10.01) = 5(10.01)^2 + 6(10.01) + 3
f(10.01) = 5(100.2001) + 60.06 + 3
f(10.01) = 501.0005 + 60.06 + 3
f(10.01) = 564.0605
Approximate value:
Since the question asks for an approximate value, we can round off the result to two decimal places:
f(10.01) ≈ 564.06
Therefore, the approximate value of f(10.01) is 564.06, which corresponds to option A.
Given function:
f(x) = 5x^2 + 6x + 3
Value to be calculated:
f(10.01)
Calculation:
Substitute x = 10.01 into the given function:
f(10.01) = 5(10.01)^2 + 6(10.01) + 3
f(10.01) = 5(100.2001) + 60.06 + 3
f(10.01) = 501.0005 + 60.06 + 3
f(10.01) = 564.0605
Approximate value:
Since the question asks for an approximate value, we can round off the result to two decimal places:
f(10.01) ≈ 564.06
Therefore, the approximate value of f(10.01) is 564.06, which corresponds to option A.
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